I cannot send an attachment but the function forms a parabola. have you tried using a graphic calculator?
GiveN:
- ABCD is a parallelogram.
- AC and BD are the diagonals.
- DE = 28 units
To FinD:
- Value of x in length of BE?
Step-wise-Step Explanation:
We know that
In any parallelogram, the diagonals (lines linking opposite corners) bisect each other. Then, AE = EC for diagonal AC and BE = DE for diagonal BD.
⇒ BE = DE
⇒ x - 4 = 28 units
⇒ x = 32 units
Hence, The required value of x here is <u>3</u><u>2</u><u> </u><u>units</u><u>.</u>
At point of intersection the two equations are equal,
hence, 6x³ =6x²
6x³-6x²=0
6x²(x-1)=0 , the values of x are 0 and 1
The points of intersection are therefore, (0,0) and (1,6)
To find the slopes of the tangents at the points of intersection we find dy/dx
for curve 1, dy/dx=12x, and the other curve dy/dx=18x²
At x=0, dy/dx=12x =0, dy/dx=18x² = 0, hence the angle between the tangents is 0, because the tangents to the two curves have the same slope which is 0 and pass the same point (0,0) origin.
At x=1, dy/dx =12x = 12, dy/dx= 18x² =18, Hence the angle between the two tangents will be given by arctan 18 -arctan 12
= 86.8202 - 85.2364 ≈ 1.5838, because the slope of the lines is equal to tan α where α is the angle of inclination of the line.
Answer:
x=2
Step-by-step explanation:
combine like terms to get 15x=30. divide by 15 on both sides to get x=2
Answer:
Step-by-step explanation:
