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Neko [114]
3 years ago
8

Five basketball players try to make as many points as possible in each game. They have a mean of 12 points per game. If the firs

t four players score 10, 14, 20, and 8 points each, how many points must the fifth player have made?
a. 20 points
b. 8 points
c. 12 points
d. 10 points​
Mathematics
2 answers:
Pavlova-9 [17]3 years ago
8 0

Answer:

12 poibts i think sorry if wrong

Alex73 [517]3 years ago
6 0
I believe it's 12 points if I'm wrong I'm sorry hope this helps
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If there were 150 people polled, how many more chose vanilla than strawberry? Question 2 options: 12 27 39 21
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Step-by-step explanation:

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3 years ago
A person is supposed to drink half a gallon of water every day.abby drank 15 small cups today if the capacity of the cup is 3.5
Yuki888 [10]

He needs to drink 3 cups MORE to meet his daily requirement.

Step-by-step explanation:

Here, as given in the question:

The total need for water = half a gallon = 0.5 gallon

1 gallon  = 128 oz

So, 0.5 gallon = 128/2  = 64 oz

Now, the capacity of 1 cup = 3.5 oz

The number of cups already drank by the person = 15 cups

So, the total amount of water already taken by him

= 15 cups x Capacity of 1 cup

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So, the amount of water left to be drink by him

= Total Need - Already covered

= 64 oz - 52 . 5 oz  =  11.5 oz

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6 0
3 years ago
In a semiconductor manufacturing process, three wafers from a lot are tested. Each wafer is classified as pass or fail. Assume t
Angelina_Jolie [31]

Answer:

P(X = 0) = 0.027

P(X = 1) = 0.189

P(X = 2) = 0.441

P(X = 3)= 0.343

Step-by-step explanation:

The probability mass function P(X = x) is the probability that X happens x times.

When n trials happen, for each x \leq n, the probability mass function is given by:

P(X = x) = pe_{n,x}.p^{x}.(1-p)^{n-x}

In which p is the probability that the event happens.

pe_{n,x}, is the permutation of n elements with x repetitions(when there are multiple events happening(like one passes and two not passing)). It can be calculated by the following formula:

pe_{n,x} = \frac{n!}{x!}

The sum of all P(X=x) must be 1.

In this problem

We have 3 trials, so n = 3

The probability that a wafer pass a test is 0.7, so p = 0.7

Determine the probability mass function of the number of wafers from a lot that pass the test.

P(X = 0) = (0.7)^{0}.(0.3)^{3} = 0.027

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P(X = 3) = (0.7)^{3} = 0.343

5 0
3 years ago
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