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inysia [295]
3 years ago
12

alex has twice as much money as jennifer. jennifer has $6 less than shannon. Together they have 54$. How much money does each ha

ve?
Mathematics
1 answer:
aleksley [76]3 years ago
3 0
54-6 = 48

48/4 (Alex-twice, Jennifer, Shannon)
48/4= 12

Alex- 12 x 2 = $24

Jennifer- 12 = $12

Shannon- 12+6 (the 6 I subtracted 54-6) = $18
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A stadium has 55,000 seats. Seats sell for ​$28 in Section​ A, ​$16 in Section​ B, and ​$12 in Section C. The number of seats in
salantis [7]
A=number of seats in section A
B=number of seats in section B
C=number of seats in section C

We can suggest this system of equations:

A+B+C=55,000
A=B+C                                      ⇒A-B-C=0
28A+16B+12C=1,158,000

We solve this system of equations by Gauss Method.

1             1              1               55,000
1            -1            -1                         0
28         16           12          1,158,000 


1             1              1               55,000
0            -2             -2             -55,000                                    (R₂-R₁)
0           12             16           382,000                                    (28R₁-R₂) 


1            1                1              55,000
0           -2              -2             -55,000
0            0                4               52,000                                     (6R₂+R₃)

Therefore:

4C=52,000
C=52,000/4
C=13,000


-2B-2(13,000)=-55,000
-2B-26,000=-55,000
-2B=-55,000+26,000
-2B=-29,000
B=-29,000 / -2
B=14,500.

A + 14,500+13,000=55,000
A+27,500=55,000
A=55,000-27,500
A=27,500.

Answer: there are 27,500 seats in section A, 14,500 seats in section B and 13,000 seats in section C.
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Step-by-step explanation:

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True. They do not share a point or side.
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