<h2>please give brainliest plz follow </h2>
<h3>The terms 4x and 5y has different variable present in it.
</h3>
<em><u>Solution:</u></em>
Given that,
<em><u>The reason is:</u></em>
When we are adding terms which has exactly the same variables, we must add the constants and let the result stand with variable
Which means,
4x + 10x = 14x
But,
We cannot add terms that has different variable
Which means,
4x + 5y
Here, both the terms 4x and 5y has different variable present in it. Hence they cannot be added together
Answer is D.) Hope I could help have a good day
To solve this, you need to plug in the numbers for <em>h</em>.
-4(-12) ≥ 8 48 ≥ 8 yes
-4(-7) ≥ 8 28 ≥ 8 yes
-4(-5) ≥ 8 20 ≥ 8 yes
-4(-3) ≥ 8 12 ≥ 8 yes
-4(-2) ≥ 8 8 ≥ 8 yes
-4(-1) ≥ 8 4 ≥ 8 no
-4(1) ≥ 8 -4 ≥ 8 no
-4(3) ≥ 8 -12 ≥ 8 no
-4(8) ≥ 8 -32 ≥ 8 no
Hope this helped!
Answer:
See below.
Step-by-step explanation:
Party A
y = x^2 + 1
For each value of x in the table, substitute x in the equation with that value and evaluate y.
x = -2: y = (-2)^2 + 1 = 4 + 1 = 5
x = -1: y = (-1)^2 + 1 = 1 + 1 = 2
Do the same for x = 0, x = 1, x = 2
x y
-2 5
-1 2
0 1
1 2
2 5
Part B
Look at points (-2, 5) and (-1, 2). The change in x from (-2, 5) to (-1, 2) is 1. The change in y is -3.
Now let's look at two other points which have a change in x of 1. Look at points (0, 1) and (1, 2). The change in x from (0, 1) to (1, 2) is 1. The change in y is 1.
You can see that for the first two points, a change of 1 in x produces a change of -3 in y, but for the second two points, the same change of 1 in x produce a change of 1 in y. Since the same change of x does not always produce the same change in y, the function is nonlinear.
Answer: A
