The type of polynomial that would best model the data is a <em>cubic</em> polynomial. (Correct choice: D)
<h3>What kind of polynomial does fit best to a set of points?</h3>
In this question we must find a kind of polynomial whose form offers the <em>best</em> approximation to the <em>point</em> set, that is, the least polynomial whose mean square error is reasonable.
In a graphing tool we notice that the <em>least</em> polynomial must be a <em>cubic</em> polynomial, as there is no enough symmetry between (10, 9.37) and (14, 8.79), and the points (6, 3.88), (8, 6.48) and (10, 9.37) exhibits a <em>pseudo-linear</em> behavior.
The type of polynomial that would best model the data is a <em>cubic</em> polynomial. (Correct choice: D)
To learn more on cubic polynomials: brainly.com/question/21691794
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Answer:
No.
Step-by-step explanation:
No, because you can multiply or divide the length and breadth of rectangle A by the same number to get B
Answer:
v = 6
u = 6√2
<h2>Hope it helps.........</h2>
The probability of drawing a red marble then a green marble would be 1/9.
In the first draw, there is a total of 10 marbles to choose from, and choosing a red marbles' probability would be 5/10, or 1/2. However in the second draw, there are only 9 marbles to choose from since you have already taken out a marble. Choosing a green marble in the second draw's probability would be 2/9. Using the rule P(A and B) = P(A) • P(B), we can also apply it to this problem "P(choosing a red marble first and then choosing a green marble second)" = 1/2 • 2/9, which is equal to 2/18. If you simplify that, you get 1/9.
There are 26 letter and 5 vowels. That means that the probability is 5/26.
Hope this helps!
