Is q(x)=3-x <br> odd,even , or neither?

How many tickets were sold in 8 hours?

Elden [556K]

Answer:

560

Step-by-step explanation:

1=160

2=320

3=480

4=640

5=800

6=960

7=1120

8=1280

9=1440

JUST ADD 160 EACH TIME

hope this is what your looking for :)

8 0

3 years ago

Help answer please!!!!

MAVERICK [17]

Answer:

QR ≈ 16.2 ft

Step-by-step explanation:

Using the tangent ratio in the right triangle.

tan62° = $\frac{opposite}{adjacent}$ = $\frac{QR}{RP}$ = $\frac{QR}{8.6}$ ( multiply both sides by 8.6 )

8.6 × tan62° = QR , then

QR ≈ 16.2 ft ( to the nearest tenth )

5 0

3 years ago

The perimeter of the scalene triangle is 54.6 cm.

valina [46]

Are you sure it’s a scalene triangle because if you only know one side and all the other sides are different lengths then it’s impossible to computer unless we know angle measures. It would have to be isoceles or we would need angle measures

5 0

3 years ago

How do you find x for this question?

lilavasa [31]

X = 32.5 I believe..........

3 0

3 years ago

How do you do this question?

Ksivusya [100]

Answer:

V = (About) 22.2, Graph = First graph/Graph in the attachment

Step-by-step explanation:

Remember that in all these cases, we have a specified method to use, the washer method, disk method, and the cylindrical shell method. Keep in mind that the washer and disk method are one in the same, but I feel that the disk method is better as it avoids splitting the integral into two, and rewriting the curves. Here we will go with the disk method.

$\mathrm{V\:=\:\pi \int _a^b\left(r\right)^2dy\:},\\\mathrm{V\:=\:\int _1^3\:\pi \left[\left(1+\frac{2}{y}\right)^2-1\right]dy}$

The plus 1 in '1 + 2/x' is shifting this graph up from where it is rotating, but the negative 1 is subtracting the area between the y-axis and the shaded region, so that when it's flipped around, it becomes a washer.

$V\:=\:\int _1^3\:\pi \left[\left(1+\frac{2}{y}\right)^2-1\right]dy,\\\\\mathrm{Take\:the\:constant\:out}:\quad \int a\cdot f\left(x\right)dx=a\cdot \int f\left(x\right)dx\\=\pi \cdot \int _1^3\left(1+\frac{2}{y}\right)^2-1dy\\\\\mathrm{Apply\:the\:Sum\:Rule}:\quad \int f\left(x\right)\pm g\left(x\right)dx=\int f\left(x\right)dx\pm \int g\left(x\right)dx\\= \pi \left(\int _1^3\left(1+\frac{2}{y}\right)^2dy-\int _1^31dy\right)\\\\$

$\int _1^3\left(1+\frac{2}{y}\right)^2dy=4\ln \left(3\right)+\frac{14}{3}, \int _1^31dy=2\\\\=> \pi \left(4\ln \left(3\right)+\frac{14}{3}-2\right)\\=> \pi \left(4\ln \left(3\right)+\frac{8}{3}\right)$

Our exact solution will be V = π(4In(3) + 8/3). In decimal form it will be about 22.2 however. Try both solution if you like, but it would be better to use 22.2. Your graph will just be a plot under the curve y = 2/x, the first graph.

5 0

3 years ago

Is q(x)=3-x odd,even , or neither?