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irinina [24]
2 years ago
5

Solve the sequence:0,5,12,23,34____​

Mathematics
1 answer:
MrRissso [65]2 years ago
4 0

Step-by-step explanation:

the answer is 49

I may not be correct

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What is the binomial expansion of (2x – 3)^5?
Tanya [424]

Answer:

C

Step-by-step explanation:

(2x + 3)^5 = C(5,0)2x^5*3^0 +

C(5,1)2x^4*3^1 + C(5,2)2x^3*3^2 + C(5,3)2x^2*3^3 + C(5,4)2x^1*3^4 + C(5,5)2x^0*3^5

Recall that

C(n,r) = n! / (n-r)! r!

C(5,0) = 1

C(5,1) = 5

C(5,2) = 10

C(5,3) = 10

C(5,4) = 5

C(5,5) = 1

= 1(2x^5)1 + 5(2x^4)3 + 10(2x^3)3^2 + 10(2x^2)3^3 + 5(2x^1)3^4 + 1(2x^0)3^5

= 2x^5 + 15(2x^4) + 90(2x^3) + 270(2x^2) + 405(2x) +243

= 32x^5 + 15(16x^4) + 90(8x^3) + 270(4x^2) + 810x + 243

= 32x^5 + 240x^4 + 720x^3 + 1080x^2 + 810x + 243

7 0
3 years ago
Read 2 more answers
2. A bakery makes muffins and cookies. Muffins are sold 18 to a box and cookies are sold 25 to a bag. They do not sell individua
Ksivusya [100]
A) if 18 muffins = 1 box,
1020 muffins = 1020/18 boxes
= 56.67 boxes

So they used 56 full boxes.

b) if 25 cookies = 1 bag
2820 cookies = 2820/25 bags
= 112.8 bags

So they used 112 full bags.

c) the remainders from a and b represent muffins and cookies left over.
8 0
2 years ago
April shoots an arrow upward at a speed of 80 feet per second from a platform 25 feet high. The pathway of the
zaharov [31]

Answer:

The maximum height of the arrow is 125 feet.

Step-by-step explanation:

The pathway of the arrow can be represented by the equation,

h = -16t^2 +80t + 25 .....(1)

Where h is height in in feet and t is time in seconds.

It is required to find the maximum height of the arrow. For maximum height, \dfrac{dh}{dt}=0.

So,

\dfrac{d(-16t^2 +80t + 25)}{dt}=0\\\\-32t+80=0\\\\t=\dfrac{80}{32}\\\\t=2.5\ s

Put t = 2.5 s in equation (1). So,

h = -16(2.5)^2 +80(2.5) + 25\\\\h=125\ \text{feet}

So, the maximum height of the arrow is 125 feet.

6 0
3 years ago
Whats 1,743 rounded to the nerest ten
ra1l [238]
1,743 rounded to the nearest ten is 1,740.
6 0
3 years ago
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What is the equation of the line that passes through the point (2, -2) and has a<br> slope of -1/2
Naddika [18.5K]
Are you looking for this ?

3 0
3 years ago
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