Answer:
C
Step-by-step explanation:
(2x + 3)^5 = C(5,0)2x^5*3^0 +
C(5,1)2x^4*3^1 + C(5,2)2x^3*3^2 + C(5,3)2x^2*3^3 + C(5,4)2x^1*3^4 + C(5,5)2x^0*3^5
Recall that
C(n,r) = n! / (n-r)! r!
C(5,0) = 1
C(5,1) = 5
C(5,2) = 10
C(5,3) = 10
C(5,4) = 5
C(5,5) = 1
= 1(2x^5)1 + 5(2x^4)3 + 10(2x^3)3^2 + 10(2x^2)3^3 + 5(2x^1)3^4 + 1(2x^0)3^5
= 2x^5 + 15(2x^4) + 90(2x^3) + 270(2x^2) + 405(2x) +243
= 32x^5 + 15(16x^4) + 90(8x^3) + 270(4x^2) + 810x + 243
= 32x^5 + 240x^4 + 720x^3 + 1080x^2 + 810x + 243
A) if 18 muffins = 1 box,
1020 muffins = 1020/18 boxes
= 56.67 boxes
So they used 56 full boxes.
b) if 25 cookies = 1 bag
2820 cookies = 2820/25 bags
= 112.8 bags
So they used 112 full bags.
c) the remainders from a and b represent muffins and cookies left over.
Answer:
The maximum height of the arrow is 125 feet.
Step-by-step explanation:
The pathway of the arrow can be represented by the equation,
.....(1)
Where h is height in in feet and t is time in seconds.
It is required to find the maximum height of the arrow. For maximum height, 
.
So,
Put t = 2.5 s in equation (1). So,
So, the maximum height of the arrow is 125 feet.
1,743 rounded to the nearest ten is 1,740.
