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stiks02 [169]
3 years ago
13

Yolanda owns 4 rabbits. She expects the number of rabbits to double every year.

Mathematics
2 answers:
klasskru [66]3 years ago
8 0
It is geometric sequence.
Therefore:
a_1=4\\
q=2\\
S=a_1*\frac{1-q^n}{1-q}\\
64=4*\frac{1-2^n}{1-2}\\
16=\frac{1-2^n}{-1}\\
-16=1-2^n\\
16+1=2^n\\
2^4+1=2^n\\
n>4

After 4 yours she will have over 64 rabbits.
Korvikt [17]3 years ago
3 0
a)\\n-after\ how\ many\ years\ will\ she\ have\ 64\ rabbits\\ \\4\cdot \frac{1-2^n}{1-2} =64\ /:4\\ \\\frac{1-2^n}{-1} =16\ \ \ \Leftrightarrow\ \ \ 2^n-1=16\ \ \ \Leftrightarrow\ \ \ 2^n=17>16\\ \\2^n>2^4\\ .\ \ \ \ \ \ \ \ \ \ \ \ \ \ a^b>a^c\ \ \wedge\ \ \ a>1\ \ \ \Rightarrow\ \ \ b>c\\n>4\\ \\Ans.\ Yolanda\ have\ 64\ rabbits\ after\ 4\ years


b)\\b-how\ much\ rabbits\ was\ in\ the\ beginning\\t-how\ many\ times\ will\ be\ an\ increase\ in\ the\ number\ of\ rabbits\\.\ \ \ \ in\ the\ years\\e-how\ many\ rabbits\ are\ expected\ Yolanda\\ \\ b\cdot \frac{1-t^n}{1-t} =e
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Answer:

y = -0.1x^2 + 250 ft

Step-by-step explanation:

Because this quadratic equation would have the curve-down form of:

y = -ax^2 + b

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If we let the peak (250 ft) of the curve be at x = 0. Then

y = -a0^2 + b = 250

b = 250

Also at the begins and ends, thats where y = 0, the 2 points are separated by 100 ft. So let the begin at -50 ft and the end at 50ft. We have

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8 0
3 years ago
bath walked 10 7/8 miles one week she walk 2 1/4 fewer miles the following week about how many miles did she walk the second wee
bagirrra123 [75]

Answer:

8 and 5/8

Step-by-step explanation:

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3x+2y=4 <br> 4x+5y=17<br> What is the value of x and y?
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{3x+2y=4    /*5
{4x+5y=17    /*(-2)

{15x+10y=20
<u>{-8x-10y=-34        </u>(+)
<em>7x=-14</em><em />
<em>x=-2</em>

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5 0
3 years ago
Read 2 more answers
Two number cubes are rolled for two separate events:
andrew11 [14]

Answer:  \bold{P(B|A)=\dfrac{P(B\cap A)}{P(A)}=\dfrac{11}{30}}

<u>Step-by-step explanation:</u>

The probability of Event B given Event A = the intersection of Event A and B divided by the probability of Event A. (see below for the symbols)

P(B|A)=\dfrac{P(B\cap A)}{P(A)}

P(A) = (1, 6), (1, 5), (1, 4), (1, 3), (1, 2), (1, 1)

          (2, 6), (2, 5), (2, 4), (2, 3), (2, 2), (2, 1)

          (3, 6), (3, 5), (3, 4), (3, 3), (3, 2), (3, 1)

                    (4, 5), (4, 4), (4, 3), (4, 2), (4, 1)

                              (5, 4), (5, 3), (5, 2), (5, 1)

                                        (6, 3), (6, 2), (6, 1)

       = 30

P(B) = (1, 2), (2, 1)                                   sum = 3

          (1, 5), (2, 4), (3, 3), (4, 2), (5, 1)    sum = 6

          (3, 6), (4, 5), (5, 4), (5, 4), (6, 3)  sum = 9

          (6, 6)                                           sum = 12

                       

      = 12

P(A ∩ B) =  (1, 2), (2, 1)

                  (1, 5), (2, 4), (3, 3), (4, 2), (5, 1)

                  (3, 6), (4, 5), (5, 4), (5, 4), (6, 3)

             = 11

7 0
3 years ago
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