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nataly862011 [7]
3 years ago
15

A 3-yard-long ribbon was used to trim for dresses. Each dress used the same amount of ribbon. How much ribbon was used for each

dress?
Mathematics
2 answers:
Tcecarenko [31]3 years ago
6 0

Answer:

For x number of dresses, the answer is 3/x.

Step-by-step explanation:

Divide the length of the ribbon by the number of dresses.

If there were x dresses, the answer is 3/x.

zepelin [54]3 years ago
3 0

Answer:

3/4 yard per dress =  2 1/4 ft per dress = 27 inches per dress

Hope this helps you!

Step-by-step explanation:

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Kirk's family drove 36 miles in 50 minutes, which was 48% of the distance to his grandmother's house. What was the total distanc
Makovka662 [10]

Answer:

Option D is correct.

75 miles is the total distance in miles to Kirk's grandmother's house

Step-by-step explanation:

Let x represents the total distance in miles to Kirk's grandmother's house.

As per the statement:

Kirk's family drove 36 miles in 50 minutes, which was 48% of the distance to his grandmother's house

⇒ Distance Kirk's family drove = 36 miles.

then;

36 = 48% of x

36 = \frac{48}{100}x

Multiply both sides by 100 we get;

3600 = 48x

Divide both sides by 48 we have;

75 miles = x

Therefore, the total distance in miles to Kirk's grandmother's house is 75 miles

4 0
3 years ago
Read 2 more answers
A cable television compan is laying cable in an area with underground utilities. Two subdivisions are located on opposite sides
Schach [20]

Answer:

Step-by-step explanation:

Given:

Point Q = Q is on the north bank 1200 m east of P $40/m to lay cable underground and $80/m way to lay the cable.

Lets denote T be a point on north bank, therefore, point T is t m east and 100m north of P.

Note that 0 < t < 1200

Distance from P to T using Pythagoras theorem:

PT^2 = PQ^2 + QT^2

PT = √(t²+100²) = √(t²+10,000)

Distance from T to Q:

TQ = 1200 - t

From above, Cable from P to T is underwater, and costs $80/m to lay.

Cable from T to Q is underground, and costs $40/m to lay.

Total cost of the cable:

C(t) = 80√(t²+10,000) + 40(1200 - t)

Cost is at its minimum: when dC/dt = C'(t) = 0 and d^2C/dt^2 = C''(t) > 0

dC/dt = C'(t)

= 80 * 1/2 (t² + 10,000)^(-1/2) × 2t + 40 × (-1)

dC/dt = C'(t)

= 80t/√(t² + 10,000) - 40 = 0

80t/√(t² + 10,000) = 40

80t = 40√(t² + 10,000)

2t = √(t² + 10,000)

square both sides:

4t² = t² + 10,000

3t² = 10,000

t² = 10,000/3

t = 100/√3

≈ 57.735

d^2C/dt^2 =

C''(t) = [80√(t² + 10,000) - 80t × t/√(t²+10,000)] /√(t²+10,000)

C''(t) = [(80(t²+10,000) - 80t²) / √(t²+10,000)] /√(t²+10,000)

C''(t) = 800,000 / (t² + 10,000)^(3/2)

C''(t) > 0 for all t

Therefore C(t) is minimized at t = 100/√3

C(100/√3) = 80√(10,000/3 + 10,000) + 40 × (1200 - 100/√3)

= 80 √(40,000/3) + 48,000 - 4000/√3

= 16000/√3 + 48,000 - 4000/√3

= 48,000 + 12,000/√3

= 48,000 + 4,000√3

= 4000 (12 + √3)

≈ 54,928.20

Minimum cost is $54,928.20

This occurs when cable is laid underwater from point P to point T(57.735 m east and 100m north of P) and then underground from point T to point Q (1200 - 57.735)

= 1142.265 m

5 0
3 years ago
If the complement of an angle is 40 less than its supplement, find the angle.
zhuklara [117]
The 2 angles in a complement would be (in degrees) 65 and 25

5 0
2 years ago
Read 2 more answers
Find the point of intersection<br> y=-3x-3<br> y=-3
Alla [95]
The answer would be -3
5 0
2 years ago
The school café charges $3 for hot lunch. This amount is automatically withdrawn from a student's lunch account each day they pu
Alexandra [31]

Answer:

15 dollars

Step-by-step explanation:

you do 3 × 5 which will give you 15

7 0
3 years ago
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