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lara31 [8.8K]
3 years ago
11

Factor the expression using the GCF. 70+95 =

Mathematics
1 answer:
olga55 [171]3 years ago
3 0

Answer:

70 + 95 = 5(14 + 19)

Step-by-step explanation:

70 + 95 = 5(14 + 19)

gcf = 5

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There are 4 circles and 8 squares. What is the simplest ratio of circles to total shapes?​
andre [41]

Answer:

4 : 12

4/ 12

4 to 12

Step-by-step explanation:

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Choose the point-slope form of the equation below that
PilotLPTM [1.2K]

Answer:

A) y-4=-1/2(x+6)

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

m=(0-4)/(2-(-6))

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m=-4/8

simplify

m=-1/2

y-y1=m(x-x1)

y-4=-1/2(x-(-6))

y-4=-1/2(x+6)

4 0
2 years ago
Pls help <br> A.<br> B.<br> C.<br> D.
Alexandra [31]

Answer:

The answer is A so put it

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ABCD is a trapezium AD and BC are parallel
Orlov [11]

Part (a)

<h3>Answer:  12.1</h3>

-----------------------

Work Shown:

We'll apply the sine rule since we have a known opposite side of AB = 10 and an unknown hypotenuse we want to find BD.

Focus on triangle ABD

sin(angle) = opposite/hypotenuse

sin(D) = AB/BD

sin(56) = 10/x

x*sin(56) = 10

x = 10/sin(56)

x = 12.062179

x = 12.1

Make sure your calculator is in degree mode.

===================================================

Part (b)

<h3>Answer:  15.1</h3>

-----------------------

Work Shown:

Draw an xy coordinate grid.

Place point A at the origin (0,0).

Point B is 10 units above this, so B is at (0,10).

Point C is at (18,10) since we move 18 units to the right of B.

Point D is at approximately (6.745085, 0). The 6.745085 is from solving tan(56) = 10/x for x.

Refer to the diagram below.

Apply the distance formula for the points C and D.

C = (x_1,y_1) = (18,10)\\\\D = (x_2,y_2) \approx (6.745085,10)\\\\

d = \text{ distance from C to D}\\\\d = \sqrt{ (x_1-x_2)^2+(y_1-y_2)^2}\\\\d \approx \sqrt{ (18-6.745085)^2+(10-0)^2}\\\\d \approx \sqrt{ 226.673112 }\\\\d \approx 15.055667\\\\d \approx 15.1\\\\

Segment CD is roughly 15.1 cm long.

3 0
3 years ago
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Find all degree solutions in the interval 0° ≤ θ &lt; 360°. If rounding is necessary, round to the nearest tenth of a degree. Us
xenn [34]

Answer:

\theta_{1} \approx 30.473^{\textdegree}

\theta_{2} \approx 120.473^{\textdegree}

\theta_{3} \approx 210.473^{\textdegree}

\theta_{4}\approx 300.473^{\textdegree}

Step-by-step explanation:

The equation needs to be rearranged in terms of one trigonometric function:

5\cdot \sin 2\theta - 9\cdot \cos 2\theta = 0

5\cdot \tan 2\theta - 9 = 0

5\cdot \tan 2\theta = 9

\tan 2\theta = \frac{9}{5}

\theta = \frac{1}{2}\cdot \tan^{-1} \left(\frac{9}{5} \right)

The tangent function has positive values in the 1st and 3rd Quadrants. Then, the solutions are:

\theta_{1} \approx 30.473^{\textdegree}

\theta_{2} \approx 120.473^{\textdegree}

\theta_{3} \approx 210.473^{\textdegree}

\theta_{4}\approx 300.473^{\textdegree}

3 0
3 years ago
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