F(x) is the same as y.......so basically ur subbing in ur points into the equation to see if it comes out equal.
f(x) = 3 - 2x.....(-2,-1)....x = -2 and f(x) = -1
-1 = 3 - 2(-1)
-1 = 3 + 2
-1 = 5.....this is not true, so it is not a solution
and that is how to do this problem.....
(-1,5)......this IS a solution
(0,3)......this IS a solution
(1,0)...this IS NOT a solution
(2,-1)...this IS a solution
Answer:
C
Step-by-step explanation:
A
(m² - 3m + 2) / (m² - m)
we see due to a little bit of experience with expressions and multiplications of expressions that
(m² - 3m + 2) = (m - 2)(m - 1)
(m² - m) = m(m - 1)
so,
(m - 2)(m - 1) / (m(m - 1)) = (m - 2) / m
so, that's not it.
B
(m² - 2m + 1) / (m - 1)
we see again
(m² - 2m + 1) = (m - 1)(m - 1)
so,
(m - 1)(m - 1) / (m - 1) = m - 1
so, that's not it.
C
(m² - m - 2) / (m² - 1)
we see again
(m² - m - 2) = (m - 2)(m + 1)
and
(m² - 1) = (m + 1)(m - 1)
so,
(m - 2)(m + 1) / ((m + 1)(m - 1)) = (m - 2) / (m - 1)
yes, that is the solution.
D
(2m² - 4m) / (2(m - 2))
2m(m - 2) / (2(m - 2)) = 2m/2 = m
no, that is not a solution.
Write f(x) / g(x) = 1 / ((x+1)(x-2)).
It's easy to see that x cannot be -1 and 2;
So all real numbers exclude -1 and 2, which matches the second choice.
Answer:
B.) 
Step-by-step explanation:
