Answer:
1000000 = 1 MLN CODES
Step-by-step explanation:
According the terms of the problems the code has 6 digits or has 6 positions.
At 1st position any of 10 digits (0,1,2,3,4,5,6,7,8 or 9 ) can put
The digits can repeated, so at position 2 any of 10 difits can put.
At position 3 again any of 10 digits can put and similarly for each of next positions can be put any of 10 digits.
So each position of the code has 10 possible variants.
To find the total number of possible codes we have to multiply the number of variants for each position to each other.
N=10*10*10*10*10*10= 10^6=1 000 000
My teacher taught me a simple equation for these types of problems:
(percent of solution × amount of solution) + (percent of solution × amount of solution) = (percent of solution × total amount of solution)
in simple terms: %amount + %amount = %total amount
We know don't know how much gallons of 60% solution we need so it will be represented as x. We dont know the total amount either so it would have to be both solutions added together so 50 + x. Now lets solve:
(0.60)(x) + (0.24)(50) = (0.50)(50 + x) simplify/ distribute
0.6x + 12 = 25 +0.5x get all xs on one side and numbers on other
0.1x + 12 = 25
0.1x = 13 divide both sides by 0.1 to find x
x = 130
You need 130 gallons of 60% solution.
Answer:
n = - 5
Step-by-step explanation:
Using the rules of exponents
× 
⇔ 
⇔ 
Consider the left side
= 
= 
= 
, then
= 
Since the bases on both sides are the same, equate the exponents
2 + n = - 3 ( subtract 2 from both sides )
n = - 5
Answer:
A = 54cm^2
Step-by-step explanation:
A = (base × height)/2
base = 9cm
height= 12cm
A = (9 × 12)/2
A = 108/2
A = 54
