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Solnce55 [7]
4 years ago
13

What is the sum of the fractions below? 3/5x+9/5x

Mathematics
1 answer:
galben [10]4 years ago
3 0

\dfrac{3}{5x}+\dfrac{9}{5x}=\dfrac{12}{5x}

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Please I need your help
Svetllana [295]

Answer:

249mm

Step-by-step explanation:

You find volume of the overall figure- 11 x 3 x 13= 429

Then find volumes of missing parts of overall complete figure and subtract from the overall volume....

5 x 4 x 3= 60

429-60=369

-------------------------------------

8 x 5 x 3= 120

369-120= 249

Hope this helped!! Hope you got it- please leave a rating and mark as Brainliest. Thank You :) (I really want to go to sleep right now, would have explained further, sorry)

8 0
3 years ago
What is an equation of the line that passes through the point (2,3) and is parallel to
Klio2033 [76]

Answer:

Which of the following is true about fiber in foods?

Group of answer choices

it is not digested

it helps one's muscles grow weaker

it is always thin and threadlike

it is bad for our bodies

Step-by-step explanation:

5 0
3 years ago
A rectangular garden has a walk around it of width x. The garden is 20 ft by 15 ft. Write a function representing the combined w
kodGreya [7K]

Answer: A(x) = 15 ft + 2x

 

EXPLANATION

 

Given,

The dimension of the rectangular garden is 20 ft by 15 ft.

Dimension of a rectangle is written as Length by Width

This implies that,

Length of the garden = 20 ft

Width of the garden = 15 ft

 

The garden has a walk around it of width x.

The combined width of the garden = Width of garden + 2x

[we are adding twice the width of the walk because it is around the garden (this means it will add to the width of the garden on both the left and right sides)]

 

Combined width of the garden, A(x) = Width of garden + 2x

Since width of the garden = 15 ft

A(x) = 15 ft + 2x

5 0
3 years ago
The hl theorem is a special case of the
yawa3891 [41]
The HL theorem is a special case of the SSS postulate.
3 0
3 years ago
Read 2 more answers
A balloon rises at the rate of 10 ft/sec from a point on the ground 100 feet from an observer. Find the rate of change of the an
lubasha [3.4K]

The rate of change of the angle of elevation of the balloon from the observer when the balloon is 100 feet above the ground is  1/20 degree/sec.

<h3>What is angle of elevation?</h3>

It is described as a relationship between an oblique line from the observer's eye to an item above his eye and the horizontal plane. This angle eventually develops above the surface. The angle of elevation is made in such a way that it is above the observer's eye, as the name suggests.

Calculation for the rate of change of angle of elevation-

According to the question,

A balloon rises at the rate of 10 ft/sec from a point on the ground 100 feet from an observer.

The balloon is 100 feet above the ground.

Let the height of the balloon be 'h' ft.

Then tanØ = h/100

h = 100tanØ

Differentiate the above equation with respect to time.

dh/dt = 100 sec² Ø (dØ/dt)

We know dh/dt = 10 ft/sec.

when h = 100

tanØ = 100/100 = 1/1

tanØ = Perpendicular/Base

On comparing above two equations,

Perpendicular = 1; Base = 1.

By Pythagoras the hypotenuse is,

H² = P² + B²

    = 1² + 1²

    = 2

H = √2

Now, calculate the value of cosØ.

cosØ = B/H = 1/√2

Squaring both side

cos² Ø = 1/2

sec² Ø = 1/cos² Ø

sec² Ø = 2

The main equation was,

dh/dt = 100 sec² Ø (dØ/dt)

Substitute the values,

dØ/dt = (dh/dt )/100 sec² Ø

         = (10)/(100×2)

dØ/dt = 1/20 degree/sec.

Therefore, the rate of change of the angle of elevation of the balloon from the observer is  1/20 degree/sec.

To know more about the angle of elevation, here

brainly.com/question/9817377

#SPJ4

8 0
2 years ago
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