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Solnce55 [7]
4 years ago
13

What is the sum of the fractions below? 3/5x+9/5x

Mathematics
1 answer:
galben [10]4 years ago
3 0

\dfrac{3}{5x}+\dfrac{9}{5x}=\dfrac{12}{5x}

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14 25/100 <br> answer please as a decimal number
shusha [124]

Answer:

14.25

Step-by-step explanation:

14 is the hole number and for the decimal part all you have to do is 25÷100

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3 years ago
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Social studies class is 4 more than two times the length of recess, in minutes.
makvit [3.9K]
Since there are no numbers, i will assume that the length of recess is 1 minute, or x. if social studies is 4 more than 2 times the length of recess, we can use the equation x*2+4 to solve the problem. the end result will be 6 minutes. Social studies is 6 minutes longer than recess
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3 years ago
What is 84 seconds to 8 seconds
Inessa05 [86]

Answer:

8 out of 84: 90% decrease

200 out of 238: 16% decrease

Step-by-step explanation:

To find a percent decrease, you first subtract the end number by the initial number. This gives you the change.

ex. 84-8=76

Now you divide the change by the initial number. You'll get a decimal.

ex. 76/84=0.904...

Multiply the decimal times 100, or move the decimal to the right twice.

ex. 0.904... -> 90.4...

Now round to the nearest ones place

ex. 90.4 -> 90%

5 0
3 years ago
The first, third and thirteenth terms of an arithmetic sequence are the first 3 terms of a geometric sequence. If the first term
Salsk061 [2.6K]

Answer:

The first three terms of the geometry sequence would be 1, 5, and 25.

The sum of the first seven terms of the geometric sequence would be 127.

Step-by-step explanation:

<h3>1.</h3>

Let d denote the common difference of the arithmetic sequence.

Let a_1 denote the first term of the arithmetic sequence. The expression for the nth term of this sequence (where n\! is a positive whole number) would be (a_1 + (n - 1)\, d).

The question states that the first term of this arithmetic sequence is a_1 = 1. Hence:

  • The third term of this arithmetic sequence would be a_1 + (3 - 1)\, d = 1 + 2\, d.
  • The thirteenth term of would be a_1 + (13 - 1)\, d = 1 + 12\, d.

The common ratio of a geometric sequence is ratio between consecutive terms of that sequence. Let r denote the ratio of the geometric sequence in this question.

Ratio between the second term and the first term of the geometric sequence:

\displaystyle r = \frac{1 + 2\, d}{1} = 1 + 2\, d.

Ratio between the third term and the second term of the geometric sequence:

\displaystyle r = \frac{1 + 12\, d}{1 + 2\, d}.

Both (1 + 2\, d) and \left(\displaystyle \frac{1 + 12\, d}{1 + 2\, d}\right) are expressions for r, the common ratio of this geometric sequence. Hence, equate these two expressions and solve for d, the common difference of this arithmetic sequence.

\displaystyle 1 + 2\, d = \frac{1 + 12\, d}{1 + 2\, d}.

(1 + 2\, d)^{2} = 1 + 12\, d.

d = 2.

Hence, the first term, the third term, and the thirteenth term of the arithmetic sequence would be 1, (1 + (3 - 1) \times 2) = 5, and (1 + (13 - 1) \times 2) = 25, respectively.

These three terms (1, 5, and 25, respectively) would correspond to the first three terms of the geometric sequence. Hence, the common ratio of this geometric sequence would be r = 25 /5 = 5.

<h3>2.</h3>

Let a_1 and r denote the first term and the common ratio of a geometric sequence. The sum of the first n terms would be:

\displaystyle \frac{a_1 \, \left(1 - r^{n}\right)}{1 - r}.

For the geometric sequence in this question, a_1 = 1 and r = 25 / 5 = 5.

Hence, the sum of the first n = 7 terms of this geometric sequence would be:

\begin{aligned} & \frac{a_1 \, \left(1 - r^{n}\right)}{1 - r}\\ &= \frac{1 \times \left(1 - 2^{7}\right)}{1 - 2} \\ &= \frac{(1 - 128)}{(-1)} = 127 \end{aligned}.

7 0
3 years ago
Which is equivalent to (-4)3
sveticcg [70]

Answer(-6)2

Step-by-step explanation:

6 0
3 years ago
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