2x + 3(8 - 3x) = 3
2x + 24 -9x = 3
-7x = -21
x = 3
y = 8 - 3x
y = 8 - 3(3)
y = 8-9
y = -1
Check the math:
2(3) + 3(-1) = 6 - 3 = 3
[tex]\begin{gathered} \text{The inequality is,} \\ 5
Answer:
-69
Step-by-step explanation:
16-(5)(16)-(5)
16x5=80
16-80-5
16-80=-64
-64-5=-69
Answer:
X = -8 and X = 2
Step-by-step explanation:
X^2 + 6X - 6 = 10
Bring the 10 over:
X^2 + 6x - 16 = 0
From here, either use the quadratic formula or
manual factorization by finding its roots:
Manually:
(X + 8)(X - 2) = 0
Equate each factor to 0 you will get:
X + 8 = 0 and X - 2 = 0
Solutions are -8 and 2 respectively.
It might be wrong but this is how i solved it: i used the elimination method to solve this and got x is 3-4y and y is all real numbers
first multiply the top equation by 5 and then you get:
5x+20y=15
-5x-20x=-15
since all the numbers are canceled out it is all real numbers.
then for x since you can’t substitute the y back in i just did:
x=3-4y
i just moved over the 4y
and to prove it you can say you substituted several points and they all worked
hope this helped let me know if you have any questions
