Answer:
j² - 5j²k - 2
Step-by-step explanation:
3j² - j²k - 6 - 4j²k - 2j² + 4
To simplify this polynomial, we can collect like terms. A term is number(s) or variable(s) that are grouped together by multiplication. <u>Like terms have the same variable and exponent</u>.
We have three groups of like terms:
The j-squares (j²), the j-squared k (j²k) and the constants (no variable).
Remember to include the negatives!
The j-squares are: 3j² ; -2j²
The j-squares k are: - j²k ; - 4j²k
The constants are: - 6 ; 4
Simplify:
3j² - j²k - 6 - 4j²k - 2j² + 4
Rearrange the polynomial by like terms
= (- j²k - 4j²k) + (3j² - 2j²) + (- 6 + 4)
Add or subtract the like terms
= (-5j²k) + (j²) + (-2)
Remove brackets and rearrange so the negative is not first
= j² + - 5j²k + - 2
Simplify where two signs are together. Adding a negative is subtraction.
= j² - 5j²k - 2 Simplified
Answer:
16.8 ÷ 8 = 2.1
( For the other ones with the " tenths " confuses because I dont know where its going gl l though )
Given that the triangle ABC is dilated by a scale factor of 1.25 to form the new triangle PQR, the dimensions of PQR will be as follows;
AB corresponds to PQ, but the length of AB=5 units, the length of PQ will be:
PQ=5*1.25=6.25 units
BC corresponds to QR, but the length if QR=4.2 units, the length of QR will be:
QR=4.2*1.25=5.25 units
lastly,
CA corresponds to RP, but CA=4 units, therefore RP will be:
4*1.25=5 units
Answer:
(x + (2), y - (4))
Step-by-step explanation:
An easy way to figure out how a shape has undergone a ridge transformation (meaning a transformation only in location and not size) is to compare corresponding points on the figure.
In this figure, use point (C) to describe the transformation. Point (C) is located at (-2, 4). However, its corresponding point (C') is located at (0,0). To go from (-2, 4) to (0,0) one has to add (2) units to the (x-coordinate) and subtract (4) units from the (y-coordinate). Therefore, the transformation can be described as the following,
(x + (2), y - (4))