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3 years ago

If -8x + 8 = 51, what does x equal?

Mathematics

2 answers:

ladessa [460]3 years ago

8 0

Step-by-step explanation:

Given

- 8x + 8 = 51

- 8x = 51 - 8

- 8x = 43

x = - 43 / 8

Hope it will help :)❤

Salsk061 [2.6K]3 years ago

8 0

X= -43 / 8 Hope this helps!!!

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One and sixty-five hundredths added to twelve and seven tenths

kolbaska11 [484]

Answer:

14.35

Step-by-step explanation:

1.65 + 12.7

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3 years ago

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Find the length of the leg(s) of a right triangle, to the nearest hundredth, if both legs are equal and the hypotenuse is 10.

charle [14.2K]

Answer:

7.07 units

Step-by-step explanation:

Use the Pythagorean theorem for the right triangle:

$\text{hypotenuse}^2=\text{leg}_1^2+\text{leg}_2^2,\\ \\c^2=a^2+b^2.$

If a = x, b = x, and c = 10, then

$10^2=x^2+x^2,\\ \\100=2x^2,\\ \\x^2=50,\\ \\x=\sqrt{50}=5\sqrt{2}\approx 7.07\ units.$

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4 years ago

After a 80% reduction, you purchase a new washing machine on sale for $56.

Daniel [21]

80% = $56
1% = $56/80 = $70
100% = $70 * 100 = $700
Original price = $700
Hope this helps.
:-)

3 0

3 years ago

Please answer correctly !!!! Will mark brainliest !!!!!!!

enyata [817]

Answer:

Step-by-step explanation:

5*5=25

25-3=22

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3 years ago

Which series of transformations will not map figure H onto itself

7nadin3 [17]

Answer:

Step-by-step explanation:

Given a square with vertices at points (2,1), (1,2), (2,3) and (3,2).

Consider option A.

1st transformation $(x+0,y-2)$ will map vertices of the square into points

$(2,1)\rightarrow (2,-1);$
$(1,2)\rightarrow (1,0);$
$(2,3)\rightarrow (2,1);$
$(3,2)\rightarrow (3,0).$

2nd transformation = reflection over y = 1 has the rule (x,2-y). So,

$(2,-1)\rightarrow (2,3);$
$(1,0)\rightarrow (1,2);$
$(2,1)\rightarrow (2,1);$
$(3,0)\rightarrow (3,2)$

These points are exactly the vertices of the initial square.

Consider option B.

1st transformation $(x+2,y-0)$ will map vertices of the square into points

$(2,1)\rightarrow (4,1);$
$(1,2)\rightarrow (3,2);$
$(2,3)\rightarrow (4,3);$
$(3,2)\rightarrow (5,2).$

2nd transformation = reflection over x = 3 has the rule (6-x,y). So,

$(4,1)\rightarrow (2,1);$
$(3,2)\rightarrow (3,2);$
$(4,3)\rightarrow (2,3);$
$(5,2)\rightarrow (1,2)$

These points are exactly the vertices of the initial square.

Consider option C.

1st transformation $(x+3,y+3)$ will map vertices of the square into points

$(2,1)\rightarrow (5,4);$
$(1,2)\rightarrow (4,5);$
$(2,3)\rightarrow (5,6);$
$(3,2)\rightarrow (6,5).$

2nd transformation = reflection over y = -x + 7 will map vertices into points

$(5,4)\rightarrow (3,2);$
$(4,5)\rightarrow (2,3);$
$(5,6)\rightarrow (1,2);$
$(6,5)\rightarrow (2,1)$

These points are exactly the vertices of the initial square.

Consider option D.

1st transformation $(x-3,y-3)$ will map vertices of the square into points

$(2,1)\rightarrow (-1,-2);$
$(1,2)\rightarrow (-2,-1);$
$(2,3)\rightarrow (-1,0);$
$(3,2)\rightarrow (0,-1).$

2nd transformation = reflection over y = -x + 2 will map vertices into points

$(-1,-2)\rightarrow (4,3);$
$(-2,-1)\rightarrow (3,4);$
$(-1,0)\rightarrow (2,3);$
$(0,-1)\rightarrow (3,2)$

These points are not the vertices of the initial square.

5 0

3 years ago