Since LM = AM, point M must be on the perpendicular bisector of AL. Since AM = BM, BL must be perpendicular to AL. This makes ∆ALC a right triangle with hypotenuse AC twice the length of side AL. Hence ∠LAC = ∠LAB = 60°, and AL is angle bisector, median, and altitude.
ΔABC is isosceles with ∠A = 120°, and ∠B = ∠C = 30°.
Pv=4,725×((1−(1+0.10÷2)^(−2
×15))÷(0.10÷2))=72,634.83
0.001 kilometers are in one meter<span />
It is A I hope that helps for you