I find it easiest to work problems of this kind using a graphing calculator. That way, extraneous solutions can be avoided. It seems to work well to rewrite the problem, so you're looking for a value of n that makes the result zero. Here, that would mean you want ...

... f(n) = √(n+5) -√(n-10) -1

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The solution by hand involves eliminating the root symbols. You do that by squaring the equation:

... n +5 -2√((n+5)(n-10)) + n -10 = 1

Now, we isolate the remaining root and square again.

... 2n -6 = 2√((n+5)(n-10)) . . . collect terms, add 2√( ) -1

... n -3 = √(n²-5n-50) . . . . . . . divide by 2

... n² -6n +9 = n² -5n -50 . . . . square both sides

... 59 = n . . . . . . . . . . . . . . . . . add 50 +6n -n²

5 0

2 years ago

Please Answer??? The binomial expansion of (2x-y)^3 is

Marina86 [1]

Your answer is B.

I hope this helped :-)

Could I have brainly-ist?

3 0

3 years ago

Read 2 more answers

The school cafeteria sells two kinds of wraps: vegetarian and chicken. The vegetarian wrap cost $1 and the chicken wrap cost$1.8

vfiekz [6]

Let us assume the number of vegetarian wraps made = x
Let us assume the number of chicken wraps made = y
Then
x + y = 70
x = 70 - y
And
x + 1.80y = 98.80
Putting the value of x from the first equation in the second equation, we get
x + 1.80y = 98.80
70 - y + 1.80y = 98.80
0.80y = 28.80
y = 36
Putting the value of y in the first equation, we get
x + y = 70
x + 36 = 70
x = 34
From the above deduction, we can conclude that the number of vegetarian warps sold was 34. I hope the answer has come to your desired help.

6 0

3 years ago