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expeople1 [14]
3 years ago
7

What is the length of segment A’B with the scale factor of 2

Mathematics
1 answer:
Nata [24]3 years ago
7 0
260 units are the answer
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What’s the correct answer for this?
jek_recluse [69]

Answer:

I believe that the answer is 24.

6 0
3 years ago
Given a rectangle with a perimeter of 24 inches, why dimensions maximize the area?
Pepsi [2]

Answer:

The dimensions are 6 by 6

Step-by-step explanation:

Calculus answer:

2x +2y= 24

xy= A

2x=24-2y

x=12-y

(12-y)(y)= 12y- y^2

the Derivative is = 12-2y

Then set that equal to zero 0=12-2y

-12=-2y

y=6

Confirm that 6 is a maximum by using a wiggle graph

wiggle graph -∞<---inc--6---dec-->∞

6 is a maximum

plug into original equation

2x + 2(6)=24

2x+12=24

2x=12

x=6

----------------------------------------------------------------------------------------------------

y=6

x=6


     



5 0
3 years ago
From 1000, create a pattern by subtracting 8 from each number and stop at 5 numbers
shusha [124]
Well subtract 8 from 1000 and then do that five times. so 992,984,976,968, and 960<span />
7 0
3 years ago
Let O be an angle in quadrant III such that cos 0 = -2/5 Find the exact values of csco and tan 0.​
vivado [14]

well, we know that θ is in the III Quadrant, where the sine is negative and the cosine is negative as well, or if you wish, where "x" as well as "y" are both negative, now, the hypotenuse or radius of the circle is just a distance amount, so is never negative, so in the equation of cos(θ) = - (2/5), the negative must be the adjacent side, thus

cos(\theta)=\cfrac{\stackrel{adjacent}{-2}}{\underset{hypotenuse}{5}}\qquad \textit{let's find the \underline{opposite side}} \\\\\\ \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies \sqrt{c^2-a^2}=b \qquad \begin{cases} c=hypotenuse\\ a=adjacent\\ b=opposite\\ \end{cases} \\\\\\ \pm\sqrt{5^2 - (-2)^2}=b\implies \pm\sqrt{25-4}\implies \pm\sqrt{21}=b\implies \stackrel{III~Quadrant}{-\sqrt{21}=b}

\dotfill\\\\ csc(\theta)\implies \cfrac{\stackrel{hypotenuse}{5}}{\underset{opposite}{-\sqrt{21}}}\implies \stackrel{\textit{rationalizing the denominator}}{-\cfrac{5}{\sqrt{21}}\cdot \cfrac{\sqrt{21}}{\sqrt{21}}\implies -\cfrac{5\sqrt{21}}{21}} \\\\\\ tan(\theta)=\cfrac{\stackrel{opposite}{-\sqrt{21}}}{\underset{adjacent}{-2}}\implies tan(\theta)=\cfrac{\sqrt{21}}{2}

4 0
2 years ago
Two weeks ago Mike ran 10 miles for his longest run ever. Yesterday, Mike ran 14 miles for a new personal record. What the the p
kiruha [24]

Answer:

40%

Step-by-step explanation:

percent change in Mike's long distance runs = (change in miles ran / initial longest mile ran) x 100

change in miles ran = new personal record - initial personal record

14 - 10 = 4

(4/10) x 100 = 40%

5 0
2 years ago
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