Answer: 1.25
Step-by-step explanation:
Given: A college-entrance exam is designed so that scores are normally distributed with a mean = 500 and a standard deviation = 100.
A z-score measures how many standard deviations a given measurement deviates from the mean.
Let Y be a random variable that denotes the scores in the exam.
Formula for z-score =
Z-score =
⇒ Z-score =
⇒Z-score =1.25
Therefore , the required z-score = 1.25
Answer:
x=5.3
Step-by-step explanation:
.3(5x-1.5)=7.5
1.5x-.45=7.5
1.5x=7.95
x=5.3
-12 and 3 add up to -9 but multiply to 36.
5=red
1/3 of all=red
1/3 of all=5
3/3 of all=all=1/3 times 3/1=5 times 3/1=15
15 total