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Mars2501 [29]
2 years ago
9

Captain Sullivan decides to plant a decoy treasure at 5 1/2, -2 3/4. Plot this point on the Coordinate Grid. Explain how you fou

nd out.
Im putting 15 points so please answer the question, if its not answered and you put a random text then I will report you so please T-T

This is my only hope its due tmr.
Mathematics
1 answer:
irinina [24]2 years ago
4 0
Ok im not quite sure what you mean but I guess you just have to go right 5 1/2 steps and then go down 2 3/4. You start from the "center" of the grid (I don't know what it's called in english..it's not my native language)
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In a standard deck of cards, what is the probability of drawing a red card or a face card? answer choices are in the form of a p
Orlov [11]

In a standard set of cards, the probability of drawing a red card or a face card is  73%

<h3>What is the probability?</h3>

In a standard deck of cards, there are 26 red cards. In that same deck, there will be 12 face cards.

The probability of picking either one is:

= (Number of face cards + Number of red cards) / Number of total cards

Solving gives:

= (12 + 26) / 52

= 38 / 52

= 73%

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1 year ago
What is the GCF for 7x2 + 21?
laiz [17]

Answer:

35

Step-by-step explanation:

<u>7x2</u>+21

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2 years ago
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2 years ago
Read 2 more answers
Sec squared 55 - tan squared 55
sergejj [24]

<u>Answer: </u>

sec squared 55 – tan squared 55  = 1

<u>Explanation:</u>

Given, sec square 55 – tan squared 55

We know that,

\sec \Theta=\frac{\text {hypotenuse}}{\text {base}}

And,

\tan \theta=\frac{\text { perpendicular }}{\text { base }}

where Ө is the angle

Substituting the values

\left(\frac{\text {hypotenuse}}{\text {base}}\right)^{2}-\left(\frac{\text { perpendicular }}{\text {base}}\right)^{2}

Solving,

\frac{(\text {hypotenuse})^{2}-(\text {perpendicular})^{2}}{(\text {base}) *(\text {base})}

According to Pythagoras theorem,

\text { (hypotenuse) }^{2}-\text { (perpendicular) }^{2}=(\text { base })^{2}

Putting this in the equation;

squared 55 - tan squared 55 =

\frac{(\text {hypotenuse})^{2}-(\text {perpendicular})^{2}}{(\text {base}) *(\text {base})}=\frac{(\text {base})^{2}}{(\text {base}) *(\text {base})}=1

Therefore, sec squared 55 – tan squared 55 = 1

6 0
3 years ago
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