The answer to this question is:
A circle is growing so that the radius is increasing at the rate of 2cm/min. How fast is the area of the circle changing at the instant the radius is 10cm? Include units in your answer.?
✔️I assume here the linear scale is changing at the rato of 5cm/min
✔️dR/dt=5(cm/min) (R - is the radius.... yrs, of the circle (not the side)
✔️The rate of area change would be d(pi*R^2)/dt=2pi*R*dR/dt.
✔️At the instant when R=20cm,this rate would be,
✔️2pi*20*5(cm^2/min)=200pi (cm^2/min) or, almost, 628 (cm^2/min)
Hoped This Helped, <span>Cello10
Your Welcome :) </span>
Answer:
-5°F
Step-by-step explanation:
As, in 2 hrs = - 10°F
For 1 hr = - 10°F/2 = - 5°F
So, answer = - 5°F
Answer:
1/21
Step-by-step explanation:
2/7 ÷ 6 =
2/7 x 1/6 = 2/42
Simplify by dividing the numerator and denominator by 2
1/21
If my answer is incorrect, pls correct me!
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-Chetan K
Standard form is y=mx+b
y=9x+4
