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Nesterboy [21]
3 years ago
11

During a snowstorm, the temperature drops from 0°F to -10°F in 2 hours. On average,by how many degrees is the temperature changi

ng per hour?
Mathematics
1 answer:
masha68 [24]3 years ago
6 0

Answer:

-5°F

Step-by-step explanation:

As, in 2 hrs = - 10°F

For 1 hr = - 10°F/2 = - 5°F

So, answer = - 5°F

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Let H = {1J4, (1 2)(3 4), (1 3)(2 4), (1 4)(2 3)
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Answer:

Please see attachment

Step-by-step explanation:

Please see attachment

3 0
3 years ago
Oregon State University is interested in determining the average amount of paper, in sheets, that is recycled each month. In pre
Juliette [100K]

Answer:

The test statistic is t = 2.79

Step-by-step explanation:

From the question we are told that

    The population mean is \mu   = 59.3

    The sample size is  n  =  79

    The  sample mean is  \= x  = 62.4

    The  standard deviation is  \sigma  =  9.86

Generally the test statistics is mathematically represented as

            t =  \frac{\= x - \mu }{ \frac{ \sigma}{ \sqrt{n} } }

substituting values

          t =  \frac{ 62.2 -  59.3 }{ \frac{  9.86}{ \sqrt{ 79} } }

          t = 2.79

4 0
4 years ago
A large university accepts 50​% of the students who apply. Of the students the university​ accepts, 35​% actually enroll. If 10,
lara31 [8.8K]

Answer:

3,500 students

Equation:

0.35 x 10,000 = 3,500

8 0
3 years ago
The family size box of Lucky Charms is 19.3 oz for $3.64.
docker41 [41]
I honestly don’t know
8 0
3 years ago
Victor spend a total of 33 picture and text messages which cost 8.30.if text message rate is .18 per message and the picture mes
malfutka [58]
Ok so

t=number of text messsages
p=number of picture messages

total number is 33
t+p=33

if text is 0.18 per pic and picture is 0.45 per text
total cost is 8.3
0.18t+0.45p=8.3
times 100 both sides for ease
18t+45p=830



we now have 2 equations
t+p=33
18t+45p=830

multiply first equation by -18 and add to second equation

18t+45p=830
<span>-18t-18p=-594 +</span>
0t+27p=236

27p=236
divide both sides by 27
p=8.740740740740744
this is impossible becasue you can't send 0.740740740740744 of a message so you did a mistype somewhere
7 0
3 years ago
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