What is the motion of a marry go round?
2 answers:
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Answer:
- 0.100
Step-by-step explanation:
Length of the ladder, H = 6 m
Distance at the bottom from the wall, B = 1.3 m
Let the distance of top of the ladder from the bottom at the wall is P
Thus,
from Pythagoras theorem,
B² + P² = H² .
or
B² + P² = 6² ..............(1) [Since length of the ladder remains constant]
at B = 1.3 m
1.3² + P² = 6²
or
P² = 36 - 1.69
or
P² = 34.31
or
P = 5.857
Now,
differentiating (1)
at t = 2 seconds
change in B = 0.3 × 2= 0.6 ft
Thus,
at 2 seconds
B = 1.3 + 0.6 = 1.9 m
therefore,
1.9² + P² = 6²
or
P = 5.69 m
on substituting the given values,
2(1.9)(0.3) + 2(5.69) × = 0
or
1.14 + 11.38 × = 0
or
11.38 × = - 1.14
or
= - 0.100
here, negative sign means that the velocity is in downward direction as upward is positive
Answer:
Square root of 4 is 2
so 1+=4
frac{[1+sqrt{2x-1]}^2 }{4}=3
so 1+sqrt{2x-1]}^2=12
so 1+sqrt{2x-1}=V12
sqrt{2x-1}=V12-1
2x-1=(V12-1)^2=12-2V12+1=13-2V12
2x=13+1-2V12
2x=14-2V12
x=7-V12
x=7-2V3
I put an attachment to explain better
Step-by-step explanation:
