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horrorfan [7]
3 years ago
9

What is another name for a relation that has each element in its domain paired with exactly one element in its range?​

Mathematics
1 answer:
Oliga [24]3 years ago
6 0
A function is a relation in which each element of the domain is paired with exactly one element of the range.
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Help me please thank you very much
Fudgin [204]

Answer:

21

Step-by-step explanation:

When we plug in the values our equation becomes,

3^3+11(2)-4(7)=

All we have to do now is solve it.

27+22-28=

49-28=21

6 0
3 years ago
5.125<br>Express that as a common fraction <br>please​
Andru [333]

Answer:

41/8

Step-by-step explanation:

4 0
3 years ago
A manufacturer of truck hoods wishes to estimate the mean weight of the hoods being produced from second shift. A sample size of
Temka [501]

Answer:

1.415

Step-by-step explanation:

The sample standard deviation will be used, so we will build the confidence interval using the student's t-distribution.

T - interval

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 8 - 1 = 7

Now, we have to find a value of T, which is found looking at the t table, with 7 degrees of freedom(y-axis) and a confidence level of 0.90(t_{90}). So we have T = 1.415

So the answer is:

1.415

5 0
3 years ago
Steps 2,4 and 6 are all justified for the same reason, what is the reason ?
mel-nik [20]

Because both of them are congruent triangles.

The have sides that equal to each other, angles that equal to each other and a common base.

5 0
4 years ago
The number of calls received by an office on Monday morning between 8:00 AM and 9:00 AM has a mean of 6. Calculate the probabili
kramer

Answer:

0.9975 = 99.75% probability of getting at least 1 call between eight and nine in the morning.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given interval

The number of calls received by an office on Monday morning between 8:00 AM and 9:00 AM has a mean of 6.

This means that \mu = 6

Calculate the probability of getting at least 1 call between eight and nine in the morning.

Either you get no calls, or you get at least one call. The sum of the probabilities of these events is decimal 1. Mathematically, we have that:

P(X = 0) + P(X \geq 1) = 1

We want P(X \geq 1). So

P(X \geq 1) = 1 - P(X = 0)

In which

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 0) = \frac{e^{-6}*(6)^{0}}{(0)!} = 0.0025

Then

[tex]P(X \geq 1) = 1 - P(X = 0) = 1 - 0.0025 = 0.9975[tex]

0.9975 = 99.75% probability of getting at least 1 call between eight and nine in the morning.

6 0
3 years ago
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