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horrorfan [7]
3 years ago
9

What is another name for a relation that has each element in its domain paired with exactly one element in its range?​

Mathematics
1 answer:
Oliga [24]3 years ago
6 0
A function is a relation in which each element of the domain is paired with exactly one element of the range.
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a rabbit's fur grows at a rate of 5/2 per month. How many months will it take for the rabbit's fur to grow 15/4 inches
UkoKoshka [18]
The answer is 1.5 months

explanation:

5/2 = 2.5

15/4 = 3.75


2.5 per month

3.75 per x months


x = (3.75×1)/2.5

x = 3.75/2.5

x = 3/2 = 1.5 months
3 0
3 years ago
The quotient of 17 and k
myrzilka [38]
The answer is 17/k because there is no exact way to divide so 17/k is the quotient. :)
8 0
3 years ago
HOw do you do this its very confusing
sesenic [268]

Answer:

Its Patrick

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Use the given transformation to evaluate the given integral, where r is the triangular region with vertices (0, 0), (8, 1), and
Jlenok [28]
We first obtain the equation of the lines bounding R.

For the line with points (0, 0) and (8, 1), the equation is given by:

\frac{y}{x} = \frac{1}{8}  \\  \\ \Rightarrow x=8y \\  \\ \Rightarrow8u+v=8(u+8v)=8u+64v \\  \\ \Rightarrow v=0

For the line with points (0, 0) and (1, 8), the equation is given by:

\frac{y}{x} = \frac{8}{1}  \\  \\ \Rightarrow y=8x \\  \\ \Rightarrow u+8v=8(8u+v)=64u+8v \\  \\ \Rightarrow u=0

For the line with points (8, 1) and (1, 8), the equation is given by:

\frac{y-1}{x-8} = \frac{8-1}{1-8} = \frac{7}{-7} =-1 \\  \\ \Rightarrow y-1=-x+8 \\  \\ \Rightarrow y=-x+9 \\  \\ \Rightarrow u+8v=-8u-v+9 \\  \\ \Rightarrow u=1-v

The Jacobian determinant is given by

\left|\begin{array}{cc} \frac{\partial x}{\partial u} &\frac{\partial x}{\partial v}\\\frac{\partial y}{\partial u}&\frac{\partial y}{\partial v}\end{array}\right| = \left|\begin{array}{cc} 8 &1\\1&8\end{array}\right| \\  \\ =64-1=63

The integrand x - 3y is transformed as 8u + v - 3(u + 8v) = 8u + v - 3u - 24v = 5u - 23v

Therefore, the integration is given by:

63 \int\limits^1_0 \int\limits^{1}_0 {(5u-23v)} \, dudv =63 \int\limits^1_0\left[\frac{5}{2}u^2-23uv\right]^{1}_0 \\  \\ =63\int\limits^1_0(\frac{5}{2}-23v)dv=63\left[\frac{5}{2}v-\frac{23}{2}v^2\right]^1_0=63\left(\frac{5}{2}-\frac{23}{2}\right) \\  \\ =63(-9)=|-576|=576
6 0
3 years ago
A sample of small bottles and their contents has the following weights (in grams): 4, 2, 5, 4, 5, 2, and 6. What is the sample v
Inessa05 [86]

Answer:

What is the sample variance of bottle weight 2.33

Step-by-step explanation:

First find the mean. The mean of the bottle weight is obtained by taking the ratio of the sum of ages and total number of ages.

Mean = (4+2+5+4+5+2+6) / 7

          = 28 / 7

          = 4

Sample Variance = \frac{\left[\begin{array}{ccc}(4-4)^{2} +(2-4)^{2} +\\(5-4)^{2} + (4-4)^{2} +\\(5-4)^{2} + (2-4)^{2} +\\(6-4)^{2}\end{array}\right]}{7-1}

                             =\frac{0+4+1+0+1+4+4}{6}

                             = 2.33

3 0
3 years ago
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