Step-by-step explanation: The central limit theorem proffers the conditions necessary to obtain a normal or bell shaped distribution. It defines normal distribution in terms of mean, standard deviation and sample size. The sample size is a very important factor in determining the shape of a distribution.

Thus with a population having mean and standard deviation stated, in other to make use of or assume normal distribution, the sample size must be large. According tho the central limit theorem, a size of greater than 30 is deemed to be large enough. As the Same size increases, the sample mean converges to the value of the population mean.

7 0

3 years ago

What is the range of this function? 5 -4 -3 -2 -1 0

Paha777 [63]

Answer:

Step-by-step explanation:

For range you will take the largest and the smallest number and subtract it.

10-2=8

7 0

4 years ago

Katie make $63.70 babysitting for 6.5 hours how much money does she make per hour? how much money would Katie earn in 5 hours?

Lubov Fominskaja [6]

Answer:She makes 9.8 an hour and 58.8 in 5 hours.

Step-by-step : You divide 63.70 by 6.5 which comes out to 9.8 which is your hourly wage then do 9.8 times 5 to get 58.8

6 0

3 years ago

The lengths of text messages are normally distributed with a population standard deviation of 4 characters and an unknown popula

umka21 [38]

Answer:

The answer is " $(25.32, 30.68)$ "

Step-by-step explanation:

Given:

$\bar x = 28\\\\ \sigma = 4\\\\n =26\\\\$

When $98\%$ confidence level so, the z:

$\alpha = 1 - 98\% = 1 - 0.98 = 0.2\\\\\frac{\alpha}{2} =\frac{0.02}{2} = 0.01\\\\Z_{\frac{\alpha}{2}} = Z_{0.01} = 1.645\ \ \ ( Using \ z \ table )\\\\$

$E = Z_{\frac{\alpha}{2} \times ( \frac{\sigma}{\sqrt{n}})$

$= 1.645 \times (\frac{4}{\sqrt{26}})\\\\=2.68$

When 98% confidence interval estimate of the population mean is,

$\bar x - E < \mu < \bar x + E\\\\28 - 2.68 < \mu < 28 + 2.68\\\\25.32 < \mu < 30.68\\\\(25.32, 30.68)\\\\$

7 0

3 years ago