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s2008m [1.1K]
3 years ago
14

What is 9*10^-5 in standard notation

Mathematics
1 answer:
kvasek [131]3 years ago
3 0

Answer:

[see answer below]

Step-by-step explanation:

9*10^{-5}

We would move the decimal 5 places to the left.

9*10^{-5}\\\\\rightarrow\boxed{0.00009}

Hope this helps!

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∠YXZ and ∠ZXW are adjacent and supplementary angles. If m∠YXZ = 37°, what is m∠ZXW?
tensa zangetsu [6.8K]
Answer: Choice A) 143 degrees

To get this answer quickly, you subtract the given angle (37) from 180 to get 180-37 = 143

The more longer answer would look something like this
x+37 = 180 .... the two supplementary angles add to 180 degrees
x+37-37 = 180-37 .... subtract 37 from both sides
x+0 = 143
x = 143
where x is the measure of angle ZXW
6 0
3 years ago
How many video games can you buy with $162 if one game $18.find equation
Umnica [9.8K]

The equation for this problem can be written as 18x=162. X would represent the number of games bought. You do the inverse operation of multiplying by 18 to both sides and you get the answer as x=9. 9 is the number of games bought with 162 dollars.

3 0
3 years ago
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Solve for x -6x + 7 > 1
Elenna [48]

the answer is 6/5

-5x>-6

x>-6/-5

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5 0
3 years ago
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On a linear X temperature scale, water freezes at −115.0°X and boils at 325.0°X. On a linear Y temperature scale, water freezes
belka [17]

Answer:

The current temperature on the X scale is 1150 °X.

Step-by-step explanation:

Let is determine first the ratio of change in X linear temperature scale to change in Y linear temperature scale:

r = \frac{\Delta T_{X}}{\Delta T_{Y}}

r = \frac{325\,^{\circ}X-(-115\,^{\circ}X)}{-25\,^{\circ}Y - (-65.00\,^{\circ}Y)}

r = 11\,\frac{^{\circ}X}{^{\circ}Y}

The difference between current temperature in Y linear scale with respect to freezing point is:

\Delta T_{Y} = 50\,^{\circ}Y - (-65\,^{\circ}Y)

\Delta T_{Y} = 115\,^{\circ}Y

The change in X linear scale is:

\Delta T_{X} = r\cdot \Delta T_{Y}

\Delta T_{X} = \left(11\,\frac{^{\circ}X}{^{\circ}Y} \right)\cdot (115\,^{\circ}Y)

\Delta T_{X} = 1265\,^{\circ}X

Lastly, the current temperature on the X scale is:

T_{X} = -115\,^{\circ}X + 1265\,^{\circ}X

T_{X} = 1150\,^{\circ}X

The current temperature on the X scale is 1150 °X.

5 0
3 years ago
Which one doesn't belong? <br> HELP PLSSSS!!!!!
Natasha2012 [34]

Answer:

The bottom right.

Step-by-step explanation:

Hope its correct.

4 0
3 years ago
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