To make 100g of jam, you need 57g of strawberries, 17g of blackberries and the rest should be sugar.

An article reported on the results of an experiment in which half of the individuals in a group of 60 postmenopausal overweight

slavikrds [6]

Answer:

Step-by-step explanation:

From the given information:

Let's first compute the null and alternative hypothesis

Null hypothesis:

$\mathbf{H_o: \mu_1-\mu_2=1}$

Alternative hypothesis:

$H_a :\mu_1 -\mu_2 > 1$

The number of samples is half in a group of 60

i.e

$n_1=n_2 = 30$

the sample mean for sample 1 $\overline x_1$ = 5.7

the standard deviation for sample 1 $s_1$ = 3.1

the sample mean for sample 2 $\overline x_2$ = 3.9

the standard deviation for sample 2 $s_2$ = 2.7

degree of freedom for this test can be computed by using the formula:

$df = \dfrac{\begin {pmatrix} \dfrac{s_1^2}{n_1} + \dfrac{s^2_2}{n_2} \end {pmatrix}^2 } {\dfrac{ (\dfrac{s_1^2}{n_1}^2)}{ n_1-1} + \dfrac{ (\dfrac{s_2^2}{n_2}^2)}{ n_2-1} }$

$df = \dfrac{\begin {pmatrix} \dfrac{3.1^2}{30} + \dfrac{2.7^2}{30} \end {pmatrix}^2 } {\dfrac{ \begin {pmatrix} \dfrac{3.1^2}{30} \end {pmatrix}^2}{ 30-1} + \dfrac{ \begin {pmatrix} \dfrac{2.7^2}{30} \end {pmatrix}^2}{ 30-1} }}$

df = 114.68

The test statistics can be computed as follows:

$t = \dfrac{ \overline x_1 -\overline x_2- (\mu_1 -\mu_2)}{\sqrt{ \dfrac{s_1^2}{n_1} +\dfrac{s_2^2}{n_2} }}$

$t = \dfrac{ 5.7-3.9- (1)}{\sqrt{ \dfrac{3.1^2}{30} +\dfrac{2.7^2}{30} }}$

t = 1.07

Using the level of significance of 0.1, the P-value for the test statistics at the df of 114.68 is:

P-value = 0.143

Decision rule: To reject the null hypothesis if the level of significance is greater than the p-value.

Conclusion: We fail to reject the null hypothesis because the p-value is greater than the level of significance at 0.1.

Thus, it appears that the true average weight loss for the vegan diet does not exceeds that for the control diet by more than 1 kg.

8 0

3 years ago

The difference between -7 and a number x is no more than -2/3

Troyanec [42]

Answer:

Pregunta muy difícil, no creo que pueda resolver este amigo.

Step-by-step explanation:there is no step-by-step thing because honestly don't understand what your trying to say here. Hmm...

8 0

3 years ago

Solve the equation for x.

Airida [17]

Answer:

D

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

The pH of lemon juice at 298 K is found to be 2. 32. What is the concentration of mc014-1. Jpg ions in the solution? Use StartBr

sdas [7]

The concentration of ions in the solution of lemon juice whose pH value is 2.32 is 4.79×10⁻³ M.

<h3>What is pH value?</h3>

The pH value shows that how much a solution is acidic or basic. The range of the pH value lies between the 0-14.

The pH value can be calculated with the following formula.

$\rm pH=log[H^{+}]$

Here, [H⁺] is the molar hydrogen ion concentration.

The pH of lemon juice at 298 K is found to be 2. 32. Put this value of pH in the above formula as,

$\rm 2.32=log[H^{+}]\\\ [H^{+}]=4.79\times10^{-3} \rm \; M$

Hence, the concentration of ions in the solution of lemon juice whose pH value is 2.32 is 4.79×10⁻³ M.

Learn more about the pH value here;

brainly.com/question/940314

8 0

2 years ago

What are the first three common multiples of 8 and 12

Nata [24]

Answer:

24, 48, 72

Step-by-step explanation:

Common Multiples of 8: 8,16,24,32,40,48,56,64,72,80….

Common Multiples of 12: 12,24,36,48,60,72,………..

Hence the First 3 Least common multiple of 8 and 12= 24, 48, 72

7 0

3 years ago