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sergeinik [125]
3 years ago
12

(06.02 MC)

Mathematics
1 answer:
Dimas [21]3 years ago
6 0

The total length of the board in terms of x is (A + B)(x) = 16x − 2

<h3 /><h3>Section A:</h3>
  • A(x) = 7x - 4

<h3>Section B:</h3>
  • B(x) = 9x - 2

Both sections indicates the length of the broken boards. Therefore,

The total length of the board in terms a x is as follows:

A(x) + B(x) = 7x - 4 + (9x + 2)

A(x) + B(x) = 7x + 9x - 4 + 2

A(x) + B(x) = 16x - 2

(A + B)(x) = 16x - 2

learn more on length: brainly.com/question/10670386?referrer=searchResults

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In a trapezoid the lengths of bases are 11 and 18. The lengths of legs are 3 and 7. The extensions of the legs meet at some poin
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Answer:  7\frac{5}{7} unit and 18 unit

Step-by-step explanation:

Let ABCD is a trapezoid where AB and CD are the bases. ( In which AB is greatest base which shown in below figure)

AD and BC are the legs of the trapezoid ABCD.

Now, we have ( According to the question ),

AB = 18 unit, BC = 7 unit, AD = 3 unit and DC = 11 unit.

Here the leg AD extends from point D.

Similarly leg BC extends from point C.

Let they meet at point P ( shown in below diagram)

Since In triangles PAB and PDC,

∠PDC ≅ ∠PAB ( because DC ║ AB )

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Therefore, By AAA similarity postulate,

\triangle PDC \sim \triangle PAB

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\frac{PD}{PA} = \frac{DC}{AB}

\frac{PD}{PD+3} = \frac{11}{18} ( because PA = PD+DA)

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Again by the definition of similarity,

\frac{PC}{PB} = \frac{DC}{AB}

\frac{PC}{PC+7} = \frac{11}{18} ( because PB = PC + CB)

⇒ 18 PC = 11 PD +77

⇒7PC = 77

⇒ PC = 11

Thus, PA =  PD+DA = 33/7 + 3 = 7\frac{5}{7}

And, PB = PC + CB = 11 + 7 = 18


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