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sergeinik [125]
3 years ago
12

(06.02 MC)

Mathematics
1 answer:
Dimas [21]3 years ago
6 0

The total length of the board in terms of x is (A + B)(x) = 16x − 2

<h3 /><h3>Section A:</h3>
  • A(x) = 7x - 4

<h3>Section B:</h3>
  • B(x) = 9x - 2

Both sections indicates the length of the broken boards. Therefore,

The total length of the board in terms a x is as follows:

A(x) + B(x) = 7x - 4 + (9x + 2)

A(x) + B(x) = 7x + 9x - 4 + 2

A(x) + B(x) = 16x - 2

(A + B)(x) = 16x - 2

learn more on length: brainly.com/question/10670386?referrer=searchResults

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Choose all the expression that have the same value as the product 0.11 and 4.5.
omeli [17]
Okay so.
A is 4.95
B is 4.95
C is 4.95
D is 4.95
E is 0.495
So I guess E is the Answer! :)
3 0
3 years ago
What is the solution to x 4 – 12x 2 + 10 &gt; 0?
Umnica [9.8K]

Answer: The picture contains the answer and the steps

5 0
3 years ago
HELP!!!!!!!!!!!!!!!!!!!!
solong [7]

Answer:

y = -1/2x+4

Step-by-step explanation:

y = 2x-1

This equation is in slope intercept form  y = mx+b  where m is the slope

m=2

A line perpendicular will have a slope that is the negative reciprocal

m = -1/2

Using the slope intercept form

y = mx+b

y = -1/2x+b

and the point given (2,3)

3 = -1/2(2)+b

3 = -1+b

4 =b

y = -1/2x+4  is the equation of a line that is perpendicular to the original line and contains (2,3)

6 0
2 years ago
We are standing on the top of a 320 foot tall building and launch a small object upward. The object's vertical altitude, measure
STALIN [3.7K]

Answer:

The highest altitude that the object reaches is 576 feet.

Step-by-step explanation:

The maximum altitude reached by the object can be found by using the first and second derivatives of the given function. (First and Second Derivative Tests). Let be h(t) = -16\cdot t^{2} + 128\cdot t + 320, the first and second derivatives are, respectively:

First Derivative

h'(t) = -32\cdot t +128

Second Derivative

h''(t) = -32

Then, the First and Second Derivative Test can be performed as follows. Let equalize the first derivative to zero and solve the resultant expression:

-32\cdot t +128 = 0

t = \frac{128}{32}\,s

t = 4\,s (Critical value)

The second derivative of the second-order polynomial presented above is a constant function and a negative number, which means that critical values leads to an absolute maximum, that is, the highest altitude reached by the object. Then, let is evaluate the function at the critical value:

h(4\,s) = -16\cdot (4\,s)^{2}+128\cdot (4\,s) +320

h(4\,s) = 576\,ft

The highest altitude that the object reaches is 576 feet.

6 0
4 years ago
In the diagram B is the midpoint of a A and C. B is also the midpoint or E and F. C is the midpoint of A and D.
aivan3 [116]

Answer:

AD = 84

Step-by-step explanation:

Since B is the midpoint of AC then AB = BC = 2x - 5

Since C is the midpoint of AD then AC = CD, thus

AB + BC = CD, that is

2x - 5 + 2x - 5 = x + 29

4x - 10 = x + 29 ( subtract x from both sides )

3x - 10 = 29 ( add 10 to both sides )

3x = 39 ( divide both sides by 3 )

x = 13

Hence

AD = AB + BC + CD

     = 2x - 5 + 2x - 5 + x + 29 = 5x + 19, thus

AD = (5 × 13) + 19 = 65 + 19 = 84

6 0
3 years ago
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