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3 years ago

What is an estimate of the solution of the equation 6n+3=2 use a table

1 answer:

4 0

The answer is -0.1666 because you would subtract 3 from both sides and then you divide -1 by 6 to get the answer <span />

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José put $1,500 into a savings account. He earns 3% interest every year. How much simple interest will he earn at the end of 3 y

stiv31 [10]

He would have a total of: $1639.09

In intrest alone he would've made 1639.09

Step-by-step explanation:

3%= 0.03

The first thing you do is multiply $1,500 by the %3 (0.03).

When your done multiplying, you should get 45.

Add 45 to 1500

Now you have 1545

Then you repeat the process over, two more times. However the numbers will change.

7 0

3 years ago

Solve y=-3x² + 4.5x – 20<br> Use the Quadratic formula

statuscvo [17]

Answer:

$x=0.75 \pm 2.47067i$

Step-by-step explanation:

Quadratic Formula: $x=\frac{-b \pm \sqrt{b^2-4ac} }{2a}$

√-1 is imaginary number i

Step 1: Define

y = -3x² + 4.5x - 20

a = -3

b = 4.5

c = -20

Step 2: Substitute and Evaluate

$x=\frac{-4.5 \pm \sqrt{4.5^2-4(-3)(-20)} }{2(-3)}$

$x=\frac{-4.5 \pm \sqrt{20.25-240} }{-6}$

$x=\frac{-4.5 \pm \sqrt{-219.75} }{-6}$

$x=\frac{-4.5 \pm \sqrt{219.75}(\sqrt{-1} ) }{-6}$

$x=\frac{-4.5 \pm i\sqrt{219.75} }{-6}$

$x=\frac{4.5 \pm i14.824 }{6}$

$x=0.75 \pm 2.47067i$

7 0

3 years ago

Please help 8th grade math

wariber [46]

Answer:

$n \geq -\frac{-29}{28}$

Step-by-step explanation:

$-3(1 - 7n) \geq -32 - 8n\\-3 + 21n \geq -32 -8n\\$

+8n +8n

$-3 + 28n \geq -32\\+3 +3\\28n \geq -29\\/28 /28\\n \geq \frac{-29}{28}$

6 0

4 years ago

A transformation is given by the rule (x,y) → (x +3, y - 8). Which of the following describes the effect of this transformation

-BARSIC- [3]

Answer:

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Thetime(inhours)requiredtorepairamachineis an exponentially distributed random variable with parameter λ = 1 . What is 2 (a) the

mihalych1998 [28]

Answer:

a) 0.1353

b) 0.3679

Step-by-step explanation:

Let's start by defining the random variable T.

T : ''The time (in hours) required to repair a machine''

T ~ exp (λ)

T ~ exp (1)

The probability density function for the exponential distribution is

(In the equation I replaced λ = L)

$f(x)=Le^{-Lx}$

With L > 0 and x ≥ 0

In this exercise λ = 1 ⇒

$f(x)=e^{-x}$

For a)

$P(T>2)$

$P(T>2)=1-P(T\leq 2)$

$P(T>2)=1-\int\limits^2_0 {e^{-x} } \, dx$

$P(T>2)=1-(-e^{-2}+1)$

$P(T>2)=e^{-2}=0.1353$

For b)

$P(T\geq 10/T>9)$

The event (T ≥ 10 / T > 9) is equivalent to the event T ≥ 1 so they have the same probability of occur

$P(T\geq 10/T>9)=P(T\geq 1)$

$P(T\geq 1)=1-P(T$

$P(T\geq 1)=1-(-e^{-1}+1)=e^{-1}=0.3679$

4 0

3 years ago