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Dimas [21]
3 years ago
13

(4x^2y^3+2xy^2-2y)-(-7x^2y^3+6xy^2-2y)

Mathematics
1 answer:
Rasek [7]3 years ago
7 0

Answer:

x y^2 (11 x y - 4)

Step-by-step explanation:

Simplify the following:

4 x^2 y^3 + 2 x y^2 - 2 y - (-7 x^2 y^3 + 6 x y^2 - 2 y)

Factor y out of -7 x^2 y^3 + 6 x y^2 - 2 y:

4 x^2 y^3 + 2 x y^2 - 2 y - y (-7 x^2 y^2 + 6 x y - 2)

-y (-2 + 6 x y - 7 x^2 y^2) = 2 y - 6 x y^2 + 7 x^2 y^3:

4 x^2 y^3 + 2 x y^2 - 2 y + 2 y - 6 x y^2 + 7 x^2 y^3

Grouping like terms, 4 x^2 y^3 + 2 x y^2 - 2 y + 2 y - 6 x y^2 + 7 x^2 y^3 = (4 x^2 y^3 + 7 x^2 y^3) + (2 x y^2 - 6 x y^2) + (2 y - 2 y):

(4 x^2 y^3 + 7 x^2 y^3) + (2 x y^2 - 6 x y^2) + (2 y - 2 y)

x^2 y^3 4 + x^2 y^3 7 = 11 x^2 y^3:

11 x^2 y^3 + (2 x y^2 - 6 x y^2) + (2 y - 2 y)

x y^2 2 + x y^2 (-6) = -4 x y^2:

11 x^2 y^3 + -4 x y^2 + (2 y - 2 y)

2 y - 2 y = 0:

11 x^2 y^3 - 4 x y^2

Factor x y^2 out of 11 x^2 y^3 - 4 x y^2:

Answer:  x y^2 (11 x y - 4)

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Now let's check

380-253= 127

CHECK

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