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4 years ago

Radio station klbj broadcasts at a frequency of 93.7 mhz. determine the length of the waves that corresponds to this frequency.

1 answer:

4 0

<span>The wavelength (in m) of a periodic wave is equal to the velocity of the wave (in m/s) divided by the frequency (in Hz). When talking about radio waves (electromagnetic radiation) that velocity is the speed of light, or 299792458 meters per second. Given a frequency of 93.7 MHz, or 93700000 Hz, the wave length is 299792458/93700000, or 3.1994926m.</span>

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Two large, parallel, conducting plates are 1.00 cm apart and having electric charges of equal magnitudes (80.0 nC/m^2) and oppos

boyakko [2]

(a) 9040 V/m

The magnitude of the electric field between two parallel, oppositely charged plates is given by

$E=\frac{\sigma}{\epsilon_0}$

where

$\sigma$ is the charge surface density on each plate

$\epsilon_0 = 8.85\cdot 10^{-12}$ is the vacuum permittivity

In this problem, the magnitude of the charge density on each plate is

$\sigma = 80.0 nC/m^2 = 80.0\cdot 10^{-9} C/m^2$

Substituting into the formula, we find the magnitude of the electric field:

$E=\frac{80.0\cdot 10^{-9}}{8.85\cdot 10^{-12}}=9040 V/m$

(b) 90.4 V

The electric potential difference between the two plates is given by

$\Delta V=Ed$

where

E is the magnitude of the electric field

d is the separation between the two plates

In this problem, we have

E = 9040 V/m

d = 1.00 cm = 0.01 m

Substituting into the formula, we find

$\Delta V=(9040)(0.01)=90.4 V$

6 0

3 years ago

An object, initially at rest, is subject to an acceleration of 45 m/s^2. How long will it take that object to travel 1000m? Roun

Romashka-Z-Leto [24]

Answer:

6.7 seconds

Explanation:

d=(1/2)at^2

equation

1000=(1/2)45t^2.

substitute

2000=45t^2.

multiply by 2 for both sides

44.44=t^2.

divide both sides by 45

6.7=t

take the square root of both sides

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