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3 years ago

an object has a velocity of 5 meters per second. to the nearest kilometer , how many kilometers will it travel in 3 days

1 answer:

5 0

Assuming that the object doesn't rest, and keeps that pace going for three days straight, first you need to calculate the the amount of meters the object can travel in one day. And to find that out you need to find the number of meters it travels per minute, which is 5 times 60, which is 300. Then calculate how far it travels per hour, which is 300 times 60, which is 18,000. Then find out how far it travels in a day, which is 18,000 times 24, which is 432,000. Then to find how many meters it travels in 3 days you multiply 432,000 by 3 which is 1,296,000. Then to find how many kilometers that is, you divide that by 1,000, which comes out to be 1296 kilometers in 3 days.

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It takes 6400 years for one gram of radium to decay away to only 1/16 (one-sixteenth) of a gram. The half-life of radium is

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3 years ago

Which statement best explains the relationship between the electric force between two charged objects and the distance between t

spin [16.1K]

Unfortunately, the given statements are missing from the problem. However, we can still determine the relationship between the electric force between two objects and the distance between them. The formula for the electric force is given below:

F = (k*Q1*Q2)/d^2

k is a constant, while Q1 and Q2 are the respective charges of the objects. F is force, while d is distance.

As seen in the formula, we can see that the electric force F is inversely proportional to the square of the distance between the two objects.

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4 years ago

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egoroff_w [7]

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3 years ago

A skateboarder traveling at 4.45 m/s can be stopped by a strong force in 1.82 s and by a weak force in 5.34 s.

ANTONII [103]

1) Impulse: $-238.5 kg m/s$

2) Strong force: -131.1 N, weak force: -44.7 N

Explanation:

The impulse exerted on an object is equal to the change in momentum of the object itself.

Mathematically:

$I=\Delta p=m(v-u)$

where

m is the mass of the object

u is the initial velocity

v is the final velocity

For the skateboarder in this problem, we have:

m = 53.6 kg

u = 4.45 m/s

v = 0 (it comes to a stop)

Therefore, the impulse is

$I=(53.6)(0-4.45)=-238.5 kg m/s$

Where the negative sign indicates that the direction is opposite to the motion of the object.

The impulse is also equal to the product between the force applied and the duration of the collision:

$I=F\Delta t$

where

I is the impulse

F is the average force

$\Delta t$ is the time during which the force is applied

The strong force is applied in a time of

$\Delta t = 1.82 s$

Therefore this force is

$F=\frac{I}{\Delta t}=\frac{-238.5}{1.82}=-131.1 N$

The weak force is applied in a time of

$\Delta t = 5.34 s$

So this force is

$F=\frac{I}{\Delta t}=\frac{-238.5}{5.34}=-44.7 N$

Learn more about impulse:

brainly.com/question/9484203

#LearnwithBrainly

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3 years ago

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3 years ago