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Simora [160]
3 years ago
6

an object has a velocity of 5 meters per second. to the nearest kilometer , how many kilometers will it travel in 3 days

Physics
1 answer:
nadezda [96]3 years ago
5 0

Assuming that the object doesn't rest, and keeps that pace going for three days straight, first you need to calculate the the amount of meters the object can travel in one day. And to find that out you need to find the number of meters it travels per minute, which is 5 times 60, which is 300. Then calculate how far it travels per hour, which is 300 times 60, which is 18,000. Then find out how far it travels in a day, which is 18,000 times 24, which is 432,000. Then to find how many meters it travels in 3 days you multiply 432,000 by 3 which is 1,296,000. Then to find how many kilometers that is, you divide that by 1,000, which comes out to be 1296 kilometers in 3 days.

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A quantum particle
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Answer: Option C.

can be represented by a wave packet.

Explanation:

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3 0
3 years ago
Monochromatic light falls on two very narrow slits 0.044 mm apart. Successive fringes on a screen 6.40 maway are 8.1 cm apart ne
shusha [124]

Answer:

The wavelength is 5.57\times10^{-7}\ m

The frequency is 5.4\times10^{14}\ Hz

Explanation:

Given that,

Distance between slits d= 0.044 mm

Distance between fringe and center of the pattern y= 8.1 cm

Distance between slits and fringes D = 6.40 m

We need to calculate the wavelength

For constructive interference

d\sin\theta=n\lambda

y=D\tan\theta

y=D\dfrac{m\lambda}{d}

\lambda=\dfrac{dy}{Dm}

Put the value into the formula

\lambda=\dfrac{0.044\times10^{-3}\times8.1\times10^{-2}}{6.40\times1}

\lambda=5.57\times10^{-7}\ m

We need to calculate the frequency

Using formula of frequency

f =\dfrac{c}{\lambda}

f=\dfrac{3\times10^{8}}{5.57\times10^{-7}}

f=5.4\times10^{14}\ Hz

Hence, The wavelength is 5.57\times10^{-7}\ m

The frequency is 5.4\times10^{14}\ Hz

8 0
3 years ago
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