6-3p>= -9 solve the inequality

sam is making a project out of wood. he needs a board that is 2 3/4 feet long. he has a board that is 3 1/8 feet long. how much

damaskus [11]

Answer:

3/8

Step-by-step explanation:

25/8 - 11/4. you multiply the whole part of the fraction to get the 25 and the 11

3 0

3 years ago

I need help with both of these problems

GREYUIT [131]

The first question is D because if the
y-intercept is 1 then every point moves down three units.

The second question is J because a vertical line is not a function so it can’t be a linear function.

8 0

4 years ago

2 3 E 4 5 I 6 8 what comes next

Georgia [21]

I think it is "N". This, because (2+3)=5 and E is the 5th letter of the alphabet. 4+5= 9 and I is the 9th letter of the alphabet. (6+8)= 14 So N should be correct I think. :)

8 0

3 years ago

Read 2 more answers

Please answer the question in the photo

Andrews [41]

Answer:

its really blurry can u post a picture with a clearer photo

Step-by-step explanation:

7 0

3 years ago

In a study to compare two different corrosion inhibitors, specimens of stainless steel were immersed for four hours in a solutio

djverab [1.8K]

Answer:

$(242-220) -1.988 \sqrt{\frac{20^2}{47} +\frac{31^2}{42}}= 10.862$

$(242-220) +1.988 \sqrt{\frac{20^2}{47} +\frac{31^2}{42}}= 33.138$

And the 95% confidence interval for the difference in the means is given by: $10.862 \leq \mu_A -\mu_B \leq 33.138$

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X_A = 242$ sample mean for inhibitor A

$s_A = 20$ sample standard deviation for inhibitor A

$n_A = 47$ sample size for A

$\bar X_B = 220$ sample mean for inhibitor B

$s_B = 31$ sample standard deviation for inhibitor B

$n_B = 42$ sample size for A

Solution to the problem

For this case the confidence interval for the difference of means is given by:

$(\bar X_A -\bar X_B) \pm t_{\alpha/2} \sqrt{\frac{s^2_A}{n_A} +\frac{s^2_B}{n_B}}$

The degrees of freedom are given by:

$df = n_A +n_B -2 = 47+42-2= 87$

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,87)".And we see that $t_{\alpha/2}=1.988$

And replacing we got:

$(242-220) -1.988 \sqrt{\frac{20^2}{47} +\frac{31^2}{42}}= 10.862$

$(242-220) +1.988 \sqrt{\frac{20^2}{47} +\frac{31^2}{42}}= 33.138$

And the 95% confidence interval for the difference in the means is given by: $10.862 \leq \mu_A -\mu_B \leq 33.138$

4 0

3 years ago