The larger fractron will be the fraction with the greater numerator.
ex. 4/5 is greater than 2/5
I am sure the correct answer is x=0.38629436…hope this help you
Answer:
11 and 16
Step-by-step explanation:
A good way to solve these is to work backwards.
X= larger and Y= smaller
if X is 5 more than 2Y than subtract 5 from the total
38 - 5 = 33
divide by 3
33/3 = 11
11 = Y and double that is 22 so add the five back into X and you get 16
Answer: A. "Segment AD bisects angle CAB." is the right answer.
Step-by-step explanation:
Given : In ΔABC ,AC≅AB.
⇒∠ACB=∠CBA....(1) (∵ angles opposite to equal sides of a triangle are equal )
Now in ΔACD and ΔABD
AD=AD (common)....(2)
Here we need one more statement to prove the triangles congruent that is only statement (A) fits in it.
If AD bisects ∠CAB then ∠CAD=∠BAD..(3)
Now again Now in ΔACD and ΔABD
∠ACB=∠CBA [from (1)]
AD=AD [common]
∠CAD=∠BAD [from (3)]
So by ASA congruency criteria ΔADC≅ΔABD.
