You need to find out if 57 can be divided evenly by a number other than 1 and 57.
57 is odd, so it is not divisible by 2.
The digits of 57 are 5 and 7. Add 5 + 7 to get 12. Since 12 is divisible by 3 (12/3 = 4), then 57 is also divisible by 3.
57/3 = 19
19 is a prime number, so the only factors of 57 are 1, 3, 19, 57.
57 rows can be divided into 19 sections of 3 rows each or 3 sections of 19 rows each.
Answer:
I think its 10
Step-by-step explanation:
hope this helps
Answer:
Step-by-step explanation:
We assume that there are 100 sour candies, Thus-
26 % of candy are grape implies that 26% of 100 candies are grape that is equal to 26
Now remaing candies that are not grape are 100-26 = 74
Based on the rule of multiplication:
P(A ∩ B) = P(A)/ P(B|A)
In the beginning, there are 26grape candies, probability of choosing first grape candy = 26C1 = 26
After the first selection, we replace the selected grape candy so there are still 100 candies in the bag P(B|A) = 100C3 = 100 x 99 x 98 x 97!/3! X 97!
= 50 x 33 x 98
So probability =1/ 50 x 33 x 98 x 26
= 1/4204200
Answer:
He should sell each pen of Rs.0.8625 so as to make a gain of 15%
Step-by-step explanation:
- Cost price of 100 pens = Rs.75
- Cost price of 1 pen= = 0.75
Gain=
SP = CP+Gain = 0.75+0.1125=0.8625
<u>So, He should sell each pen of Rs.0.8625 so as to make a gain of 15%</u>
#Learn more:
By selling 60 pens a shopkeeper gain the cp of 15 pen. If he bought 20 pens in rs36. Find the sp of one pen
brainly.in/question/15083989
https://brainly.in/question/7469007
Answer:y=6.61,x=-6.46
Step-by-step explanation:
3x+7y=-26(×5)
-
5x+3y=-14(×3)
=15x+35y=-130
-
15x+9y=-42
subtracting the 2 equations =15x-15x+35y-9y=-130-(-42)
=26y=172
y=172÷26
y=6.61
substitute y in the first equation=3x+6.61=-26
3x=-26+6.61=-19.39
x=-19.39÷3
x=-6.46