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zmey [24]
3 years ago
9

If Logan has $30.67 and Jenny has $12.69 how much more does Logan have than Jenny

Mathematics
2 answers:
e-lub [12.9K]3 years ago
7 0
17,98 $ (subtraction)
Hope that helpful ! 
maksim [4K]3 years ago
6 0
30.67-12.69=17.98
Therefore, Logan has $17.98 more than Jenny
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Suppose that one wishes to schedule vehicles from a central depot to five customer locations. The distance of making trips betwe
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Answer:

The routing suggested by the savings method is route (3,4)

Step-by-step explanation:

Savings for all trips (i, j), 1 ≤ i ∠ j ≤ 5

Total  number of trips to be commuted = 10 trips

S₁₂ = C₀₁ + C₀₂ - C₁₂ = 20 + 75 - 35 = 60

S₁₃ = C₀₁ + C₀₃ - C₁₃ = 20 + 33 - 5 = 48

S₁₄ = C₀₁ + C₀₄ - C₁₄ = 20 + 10 - 20 = 10

S₁₅ = C₀₁ + C₀₅ - C₁₅ = 20 + 30 - 15 = 35

S₂₃ = C₀₂ + C₀₃ - C₂₃ = 75 + 33 - 18 = 90

S₂₄ = C₀₂ + C₀₄ - C₂₄ = 75 + 10 - 58 = 27

S₂₅ = C₀₂ + C₀₅ - C₂₅ = 75 + 30 - 42 = 63

S₃₄ = C₀₃ + C₀₄ - C₃₄ = 33 + 10 - 40 = 3

S₃₅ = C₀₃ + C₀₅ - C₃₅ = 33 + 30 - 20 = 43

S₄₅= C₀₄ + C₀₅ - C₄₅ = 10 + 30 - 25 = 15

3 0
3 years ago
A gold alloy contains 15 milligrams of gold for every 4 milligrams of copper. A jeweler uses 48 milligrams of copper to make the
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Answer:

There are 180 milligrams of gold in the alloy

Step-by-step explanation:

because i know

7 0
2 years ago
Which accurately labels the cytoplasm?<br><br> W<br> X<br> Y<br> Z
bogdanovich [222]
<h2>Hey there! </h2>

<h2>The accurate answer is:</h2>

<h3>Option Y</h3>

<h2>Hope it help you </h2>
6 0
3 years ago
Read 2 more answers
Solve for x. 7(x - 3) 3(4 - x) = -8 x = 1/4 x = 25/10 x = -16/19 x = -41/10
Ann [662]
7(x - 3) + 3(4 - x) = -8
7x - 21 + 12 - 3x = -8
7x - 3x = -8 + 21 - 12
4x = 1
x = 1/4
5 0
3 years ago
A small business owner estimates his mean daily profit as $970 with a standard deviation of $129. His shop is open 102 days a ye
Katena32 [7]

Answer:

The probability that the shopkeeper's annual profit will not exceed $100,000 is 0.2090.

Step-by-step explanation:

According to the Central Limit Theorem if we have a population with mean <em>μ</em> and standard deviation <em>σ</em> and we select appropriately huge random samples (<em>n</em> ≥ 30) from the population with replacement, then the distribution of the sum of values of <em>X</em>, i.e ∑<em>X</em>, will be approximately normally distributed.  

Then, the mean of the distribution of the sum of values of X is given by,  

 \mu_{x}=n\mu

And the standard deviation of the distribution of the sum of values of X is given by,  

 \sigma_{x}=\sqrt{n}\sigma

The information provided is:

<em>μ</em> = $970

<em>σ</em> = $129

<em>n</em> = 102

Since the sample size is quite large, i.e. <em>n</em> = 102 > 30, the Central Limit Theorem can be used to approximate the distribution of the shopkeeper's annual profit.

Then,

\sum X\sim N(\mu_{x}=98940,\ \sigma_{x}=1302.84)

Compute the probability that the shopkeeper's annual profit will not exceed $100,000 as follows:

P (\sum X \leq  100,000) =P(\frac{\sum X-\mu_{x}}{\sigma_{x}}

                              =P(Z

*Use a <em>z</em>-table for the probability.

Thus, the probability that the shopkeeper's annual profit will not exceed $100,000 is 0.2090.

6 0
2 years ago
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