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kvv77 [185]
3 years ago
12

Which set of side lengths is a Pythagorean triple? 2, 3, 13 5, 7, 12 10, 24, 29 11, 60, 61

Mathematics
2 answers:
elena-14-01-66 [18.8K]3 years ago
7 0
11, 60, 61 side lengths are a pythagorean triple.
goldenfox [79]3 years ago
6 0

Answer: The correct answer is "11,60 and 61".

Step-by-step explanation:

The expression from the Pythagoras theorem in the right triangle is as follows;

AC^{2} =BC^{2} + AB^{2}                      ...... (1)

Here, AC is the longest side which is hypotenuse, AB is the shortest side which is perpendicular in the right triangle and BC is the side of the triangle.

Only 11, 60 and 61 satisfies the above expression.

(61)^{2} =(60)^{2} + (11)^{2}

3721=3600+121

3721=3721  

Therefore, L.H.S is equal to R.H.S. It satisfies the Pythagoras theorem.

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2x-y=-6<br>3x-4y=-4<br>Solve using elimination and then substitution
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Okay, so first you are going to decide whether to solve for x or solve for y. I am going to solve for x. In order to do so, you must get x by itself.
2x-y=-6
2x=y-6[ [tex]3x-4y=-4
3x=4y-4 \\ x= \frac{4y-4}{3}
The next step is to set both equations equal to each other in order to find y.
\frac{y-\frac{y-6}{2}= \frac{4y-4}{3} \\ 3(y-6)=2(4y-4) \\ 3y-18=8y-8 \\ -10=5y \\ y=-26}{2} [/tex]

So now you know that y=-2. The next part is substitution. All you have to do is pick on of the equations and plug in the y value to get the x value.

So your answer to the question is (-4,-2). I hope I've helped you understand how to solve these types of problems. If you have any questions, don't hesitate to ask.

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Step-by-step explanation:

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