<h3>
Answer: B) Complex numbers</h3>
Complex numbers are always in the form a+bi with 'a' and 'b' as real numbers.
If b = 0 and 'a' is nonzero, then a+bi = a+0i = a which is strictly a real number
If a = 0 and b is nonzero, then a+bi = 0+bi = bi indicating that the number is now purely imaginary
Answer:
2m+8
Step-by-step explanation:
<span>(1,625) No
(0,-25) No
(-1,-1) No
Think about what an integer exponent means for an negative base and you'll understand this problem. For instance the powers of -25 would be
-25^1 = -25
-25^2 = (-25) * (-25) = 625
-25^3 = (-25)*(-25)*(-25) = -15625
and so on, giving 390625, -9765625, 244140625, etc.
But that's a different subject. For the ordered pairs given, let's check them out.
(1,625)
-25^1 + 1 = -25 + 1 = -24. And -24 is not equal to 625, so "No".
(0,-25)
-25^0 + 1 = 1 +1 = 2.
Note: Any real number other than 0 raised to the 0th power is 1. And 2 is not equal to -25, so "No".
(-1,-1)
-25^(-1) + 1 = 1/(-25^1) + 1 = 1/-25 + 1 = 24/25.
And 24/25 is not equal to -1, so also "No".</span>
The intensity level is hard and for the first part, it’s 168. and something. Sorry that’s all I figured out I’m not too smart :/
Solving radical equations are different because you would want to get everything in the equation to rational numbers.
Extraneous solutions arise when you manipulate the equation. After manipulating if a solution is found that can not satisfy the original equation(s).
