1. X less than of equal to (<_) -10
2. 2y > -5/2
First, lets create a equation for our situation. Let

be the months. We know four our problem that <span>Eliza started her savings account with $100, and each month she deposits $25 into her account. We can use that information to create a model as follows:
</span>

<span>
We want to find the average value of that function </span>from the 2nd month to the 10th month, so its average value in the interval [2,10]. Remember that the formula for finding the average of a function over an interval is:

. So lets replace the values in our formula to find the average of our function:
![\frac{25(10)+100-[25(2)+100]}{10-2}](https://tex.z-dn.net/?f=%20%5Cfrac%7B25%2810%29%2B100-%5B25%282%29%2B100%5D%7D%7B10-2%7D%20)



We can conclude that <span>the average rate of change in Eliza's account from the 2nd month to the 10th month is $25.</span>
Answer:
4 Soccer balls and 6 Basketballs
Step-by-step explanation:
You can solve this problem by setting up a system of equations. Letting x be Soccer balls and y be Basketballs. Remember, Money goes with, Money goes with Money, meaning that for this problem the first equation that can be made is $248 = $28y + $20x with Y being basketballs and x being soccerballs. Next is a little more difficult. You will be creating the equation y=3x-6 because it is 6 less than 3 times the amount of x or Soccer balls. From here you can plug in the equations into a graphing calculator and graph it and see where the two lines intersect. This would be at (4, 6). When I said to let x equal Soccer Balls and y equal basketballs that is where I got the 4 soccer balls and 6 basketballs.
-2w)23x45(8w9x4) this might be right
( n + 7 ) x 3
Hope it is right