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Alekssandra [29.7K]
3 years ago
7

Eliza started her savings account with $100. Each month she deposits $25 into her account. Determine the average rate of change

in Eliza's account from the 2nd month to the 10th month. Show all work for full credit.
Mathematics
1 answer:
Afina-wow [57]3 years ago
6 0
First, lets create a equation for our situation. Let x be the months. We know four our problem that <span>Eliza started her savings account with $100, and each month she deposits $25 into her account. We can use that information to create a model as follows:
</span>f(x)=25x+100
<span>
We want to find the average value of that function </span>from the 2nd month to the 10th month, so its average value in the interval [2,10]. Remember that the formula for finding the average of a function over an interval is: \frac{f(x_{2})-f(x_{1})}{x_{2}-x_{1} }. So lets replace the values in our formula to find the average of our function:
\frac{25(10)+100-[25(2)+100]}{10-2}
\frac{350-150}{8}
\frac{200}{8}
25

We can conclude that <span>the average rate of change in Eliza's account from the 2nd month to the 10th month is $25.</span>
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Answer:

Option D. is the correct option.

Step-by-step explanation:

In this question expression that represents the kth term of a certain sequence is not written properly.

The expression is (-1)^{k+1}(\frac{1}{2^{k}}).

We have to find the sum of first 10 terms of the infinite sequence represented by the expression given as (-1)^{k+1}(\frac{1}{2^{k}}).

where k is from 1 to 10.

By the given expression sequence will be \frac{1}{2},\frac{(-1)}{4},\frac{1}{8}.......

In this sequence first term "a" = \frac{1}{2}

and common ratio in each successive term to the previous term is 'r' = \frac{\frac{(-1)}{4}}{\frac{1}{2} }

r = -\frac{1}{2}

Since the sequence is infinite and the formula to calculate the sum is represented by

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S=\frac{\frac{1}{2} }{1+\frac{1}{2}}

S=\frac{\frac{1}{2}}{\frac{3}{2} }

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Now we are sure that the sum of infinite terms is \frac{1}{3}.

Therefore, sum of 10 terms will not exceed \frac{1}{3}

Now sum of first two terms = \frac{1}{2}-\frac{1}{4}=\frac{1}{4}

Now we are sure that sum of first 10 terms lie between \frac{1}{4} and \frac{1}{3}

Since \frac{1}{2}>\frac{1}{3}

Therefore, Sum of first 10 terms will lie between \frac{1}{4} and \frac{1}{2}.

Option D will be the answer.

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