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liubo4ka [24]
3 years ago
15

PLEASE HELP THANK YOU!!!!

Mathematics
1 answer:
insens350 [35]3 years ago
3 0
//// For G(x) = -1/4x - 1////
G(-5) = -1/4(-5) - 1 = 0.25;
G(-2) = -1/4(-2) - 1 = -0.25;
G(-1) = -1/4(-1) - 1 = -0.75;
///////////////////////////////////

////For G(x) = (x-1)^2 - 3////
G(-1) = ((-1) -1)^2 - 3 = 1;
G(-2) = ((-2) - 1)^2 - 3 = 6;
G(-5) = ((-5) - 1)^2 - 3 = 33;
//////////////////////////////////////////

////For G(x) = 1/4x + 2////////
G(-5) = 1/4(-5) + 2 = 0.75;
G(-2) = 1/4(-2) + 2 = 1.5;
G(-1) = 1/4(-1) + 2 = 1.75;

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Help me solve this????
Grace [21]

Price of movie ticket in Japan is x=7.362$

Price of movie ticket in Switzerland is y=13.652$

Step-by-step explanation:

Let, Price of movie ticket in Japan is x

Price of movie ticket in Switzerland is y

Statement 1 : Total of 79.39$ of three movie ticket in Japan and two movie ticket in Switzerland

We write, 3x+2y=79.39        ( Equation 1 )

Statement 1 : Total of 75.68$ of two movie ticket in Japan and three movie ticket in Switzerland

We write, 2x+3y=75.68        ( Equation 2 )

Solving by method of elimination

Multiplying equation 1 by 2, we get

6x+4y=158.78

Multiplying equation 2 by 3, we get

6x+9y=227.04

Subtracting both the linear equation,

  6x+4y=158.78

- 6x+9y=227.04

_______________

 0x-5y=(158.78-227.04)

-5y=(-68.26)

5y=68.26

y=13.652$

Replacing value of y in any equation

3x+2y=79.39

3x+2(13.652 )=79.39

x=17.362$

Thus,

Price of movie ticket in Japan is x=7.362$

Price of movie ticket in Switzerland is y=13.652$

3 0
3 years ago
Consider this equation. cos(θ)= -3/10 If θis an angle in quadrant II, what is the value of tan (θ)?
Alja [10]

Answer:

C)

Step-by-step explanation:

Trigonometry ratio:

         \sf Cos \ \theta = \dfrac{Adjacent \ side}{hypotenuse}=\dfrac{-3}{10}

We need to find the opposite side using Pythagorean theorem.

 opposite side² = hypotenuse² - adjacent side²

                           = 10² - (-3)²

                            = 100 - 9

                           = 91

opposite side    = √91

                 \sf tan \ \theta = \dfrac{opposite \ side}{adjacent \ side}

                           \sf = \dfrac{\sqrt{91}}{3}

In quadrant II, value of tan \theta is negative.

              \sf tan \ \theta = -\dfrac{\sqrt{91}}{3}

7 0
2 years ago
If you flip a coin 4 times, how many times it is most likely to land with heads up?
TEA [102]
If you flip it at a certan hight than all 4
4 0
3 years ago
Which of these choices show a pair of equivalent expressions?
hoa [83]

Answer:

C AND D

Step-by-step explanation:

AP EX Confirmed

7 0
2 years ago
(08.04 MC)
skelet666 [1.2K]

Answer:

292,968

Step-by-step explanation:

As we know,

Sum of a geometric sequence (S) = \frac{a(1-r^{n}) }{(1-r)}

where,

a = first term of sequence,

r = the constant ratio,

n = number of terms in sequence.

So, according to the question,

a = 3,

r = 5,

n = 8.

by substituting the values in the above formula, we get;

⇒ S=\frac{3(1-5^{8}) }{(1-5)}

⇒ 292,968

7 0
3 years ago
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