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liubo4ka [24]
4 years ago
15

PLEASE HELP THANK YOU!!!!

Mathematics
1 answer:
insens350 [35]4 years ago
3 0
//// For G(x) = -1/4x - 1////
G(-5) = -1/4(-5) - 1 = 0.25;
G(-2) = -1/4(-2) - 1 = -0.25;
G(-1) = -1/4(-1) - 1 = -0.75;
///////////////////////////////////

////For G(x) = (x-1)^2 - 3////
G(-1) = ((-1) -1)^2 - 3 = 1;
G(-2) = ((-2) - 1)^2 - 3 = 6;
G(-5) = ((-5) - 1)^2 - 3 = 33;
//////////////////////////////////////////

////For G(x) = 1/4x + 2////////
G(-5) = 1/4(-5) + 2 = 0.75;
G(-2) = 1/4(-2) + 2 = 1.5;
G(-1) = 1/4(-1) + 2 = 1.75;

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RoseWind [281]

Answer:

(a)∴A=$6753.71.

(b)∴A=$1480.24

(c) ∴P=$7424.70

(d)∴P=$49759.62

(e)∴P=$5040.99

(f) ∴P=$2496.11

Step-by-step explanation:

We use the following formula

A=P(1+\frac rn)^{nt}

A=amount in dollar

P=principal

r=rate of interest

(a)

P=$2,500, r=5%=0.05,t =20 years , n= 4

A=\$2500(1+\frac{0.05}{4})^{(20\times 4)

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∴A=$6753.71.

(b)

P=$1,000, r=8% =0.08,t =5 years , n= 2

A=\$1000(1+\frac{0.08}{2})^{(5\times 2)

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∴A=$1480.24

(c)

A=$10,000, r=6% =0.06,t =5 years , n= 4

10000=P(1+\frac{0.06}{4})^{(5\times 4)}

\Rightarrow P=\frac{10000}{(1+0.015)^{20}}

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(d)

A=$100,000, r=6% =0.06,t =10 years , n= 12

100000=P(1+\frac{0.07}{12})^{(10\times 12)}

\Rightarrow P=\frac{100000}{(1+\frac{0.07}{12})^{120}}

\Rightarrow P=49759.62

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(e)

A=$100,000, r=10% =0.10,t =30 years , n= 12

100000=P(1+\frac{0.10}{12})^{(30\times 12)}

\Rightarrow P=\frac{100000}{(1+\frac{0.10}{12})^{360}}

\Rightarrow P=5040.99

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(f)

A=$100,000, r=7% =0.07,t =20 years , n= 4

100000=P(1+\frac{0.07}{4})^{(20\times 4)}

\Rightarrow P=\frac{100000}{(1+\frac{0.07}{4})^{80}}

\Rightarrow P=2496.11

∴P=$2496.11

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svetoff [14.1K]

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