12,480 es par y la suma de sus digitos da un multiplo de 3, por ello concluimos que es divisible por 6.
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¿Como saber si un número es divisible por 6?</h3>
Para que un número sea divisible por 6 debe cumplir dos condiciones.
- Ser par.
- La suma de sus digitos debe ser multiplo de 3.
En este caso tenemos 12,480, que sabemos que es par.
La suma de sus digitos da:
1 + 2 + 4 + 8 + 0 = 15
15 es multiplo de 3.
Entonces este número cumple ambas condiciones, por lo que concluimos que 12,480 es divisible por 6.
Sí quieres aprender más sobre divisiones.
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Answer:
Step-by-step explanation:
A = L * W
A = 22
L = 2x + 1
W = 3x + 1
now we sub
22 = (2x + 1)(3x + 1)
22 = 6x^2 + 2x + 3x + 1
22 = 6x^2 + 5x + 1
6x^2 + 5x + 1 - 22 = 0
6x^2 + 5x - 21 = 0 <======part A
(3x + 7)(2x - 3) = 0
3x + 7 = 0 2x - 3 = 0
3x = -7 2x = 3
x = -7/3 x = 3/2
I believe that x = -7/3 is an extraneous solution because when u plug it into ur length and width u get a negative number....and I dont think the sides of ur rectangle have negative values, however, it does work in ur equation and it equals 22 when multiplied...so I am not 100% sure
length = 2x + 1.......2(3/2) + 1........3 + 1 = 4
width = 3x + 1......3(3/2) + 1......9/2 + 1......9/2 + 2/2 = 11/2 (or 5.5) meters <===
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Answer:</h3>
x = 4.8
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Step-by-step explanation:</h3>
With angles like this these ones, the 2 lines equal the same amount. To find the length of one of the lines, you multiply the given lengths.
So, for the first angle, the line with both angles has a 4 and 6, so the length of the line is 24.
Since the lines are equal, to find the length of x you take 24 and divide it by 5, which gives you 4.8, or 24/5.
This means x = 4.8.
To double check, you can simply multiply 4 and 6, then 5 and 4.8. If the answers are the same, it is correct.
<u><em>This applies to all 3 angles shown. </em></u>
<em>Hope this helps!</em>
<em>Visual Explanation:</em>
Answer:
the first one
Step-by-step explanation:
the two planes intersect at line YZ, where they meet
tip: planes intersects at a line, just like how lines intersect at a point
hope this helps :)
That’s easy There you go wait why isn’t it letting me put it