Answer:
Code
Explanation:
The code is instructions that you can write yourself or download from online
Answer:
#include <iostream>
using namespace std;
double DrivingCost(int drivenMiles,double milesPerGallon,double dollarsPerGallon)
{
double dollarsperMile=dollarsPerGallon/milesPerGallon;//calculating dollarsperMile.
return dollarsperMile*drivenMiles;//returning thr driving cost..
}
int main() {
double ans;
int miles;
cout<<"Enter miles"<<endl;
cin>>miles;
ans=DrivingCost(miles,20.0,3.1599);
cout<<ans<<endl;
return 0;
}
Output:-
Enter miles
10
1.57995
Enter miles
50
7.89975
Enter miles
100
15.7995
Explanation:
In the function first I have calculated the dollars per mile and after that I have returned the product of dollarspermile and driven miles.This will give the cost of the Driving.
Well potential energy is energy that is in a object while its not moving so i would go your third option
Answer:
es biene por que es de el no es prestada asi que es biene
Answer:
Written in C++
void number(int n){
if(n%2 == 0)
cout<<2 * n;
else
cout<<5 * n;
}
Explanation:
The programming language is not stated.
However, I answered using C++
This line defines the function as void
void number(int n){
This line checks if the number is even
if(n%2 == 0)
If yes, it doubles the number and prints the output
cout<<2 * n;
If otherwise,
else
It multiplies the number by 5 and prints the output
cout<<5 * n;
}
To call the function from main, use:
number(n);
Note than n must be declared as integer
See attachment
