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ololo11 [35]
3 years ago
6

What is the value of x in the equation-2/3x+9=4/3x-3

Mathematics
1 answer:
Ronch [10]3 years ago
3 0

Answer:

6

Step-by-step explanation:

-\frac{2}{3} x+9=\frac{4}{3} x-3\\\\

First, multiply both sides by 3.

-2x+27=4x-9\\

Next, combine like terms.

-2x+27=4x-9\\-2x+36=4x\\36=6x

Solve for x.

36=6x\\6=x

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A piece of cardboard is 15 inches by 30 inches. A square is to be cut from each corner and the sides folded up to make an open-t
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Answer:

Maximum volume = 649.519 cubic inches

Step-by-step explanation:

A rectangular piece of cardboard of side 15 inches by 30 inches is cut in such that a square is cut from each corner. Let x be the side of this square cut. When it was folded to make the box the height of box becomes x, length becomes (30-2x) and the width becomes (15-2x).

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Equating the first derivative to zero, we get,

\frac{d(V(x))}{dx} = 0\\\\12x^2 - 180x +450 = 0

Solving, with the help of quadratic formula, we get,

x = \displaystyle\frac{5(3+\sqrt{3})}{2}, \frac{5(3-\sqrt{3})}{2},

Again differentiation V(x), with respect to x, we get,

\frac{d^2(V(x))}{dx^2} = 24x - 180

At x =

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\frac{d^2(V(x))}{dx^2} < 0

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x = \displaystyle\frac{5(3-\sqrt{3})}{2} for V(x).

Thus, largest volume the box can have occurs when x = \displaystyle\frac{5(3-\sqrt{3})}{2}}.

Maximum volume =

V(\displaystyle\frac{5(3-\sqrt{3})}{2}) = (30 - 2x)(15-2x)x = 649.5191\text{ cubic inches}

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