Answer:
(f^−1)′(6)=1/(f'(f^-1(6)))
(f^−1)′(6)=1/(f'(f^-6)))
I hope this helps.
Answer:
2(x + 4) / 6(x² - 3x - 28)
Step-by-step explanation:
Area of a rectangle = length × width
Length = 2/(x² - 3x - 28)
Width = x² - 16/6x - 24
= (x + 4)(x - 4) / 6(x - 4)
= (x + 4) / 6
Area of a rectangle = length × width
= 2/(x² - 3x - 28) × (x + 4) / 6
= 2(x + 4) / (x² - 3x - 28)6
= 2(x + 4) / 6x² - 18x - 168
= 2(x + 4) / 6(x² - 3x - 28)
Area of a rectangle =
2(x + 4) / 6(x² - 3x - 28)
1.0g/cm3 means that the mass of one cm3 is 1.0g
The easiest method to use is the rule of three, and let x be the mass of 10.0 cm3 of water
1g -- > 1.0 cm3
x --> 10.0 cm3
x= (10*1)/1
x=10.0 g
So the mass of 10.0 cm3 of water is 10.0g
Hope this Helps! :)
Answer:
12.4
Step-by-step explanation:
