Question

What is the area of a regular pentagon with side length 20 feet? Can u guys show steps pls.

Answer 1

Answer:

$688.19m^2$

Step-by-step explanation:

$A=\frac{1}{4} \sqrt{5(5+2\sqrt{5} } a^2\\=\frac{1}{4} \sqrt{5(5+2\sqrt{5} }* 20^2\\=688.19096m^2\\=688.191m^2\\=688.19m^2$