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RUDIKE [14]
3 years ago
6

Please help. Thanks!

Mathematics
1 answer:
Naddik [55]3 years ago
8 0

Answer:

84.9%

Step-by-step explanation:

First we need to calculate the total number of people. Total number of people will be the sum of all the given frequencies of all classes. There are 9 classes in total that are shown on the histogram

So,

Total number of people = 40 + 40 + 35 + 35 + 25 + 25 + 25 + 25 + 15 = 265

Now we need the number of people who took less than 40 seconds. This will be equal to sum of all frequencies below the time 40 seconds. i.e.

Number of people who took less than 40 seconds = 40 + 40 + 35 + 35 + 25 + 25 + 25 = 225

Formula to calculate percentage is:

Percentage = \frac{\text{Desired Part}}{\text{Total}} \times 100\%

So, percentage of people who took less than 40 seconds = \frac{225}{265} \times 100\% = 84.9\%

Thus, 84.9% of people took less than 40 seconds to complete the task.

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olganol [36]

Answer:

b=(-10-a)/4

First factor out the common number:3

Then divide both sides by 3

Then simplify 30/3 to 10

Then subtract a to get your answer

5 0
3 years ago
What is the solution to the system of equations graphed below
aliina [53]
The point where the lines intersect is the point that satisfies both equations.

It is (1, 5), selection C.
3 0
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A bag of balloons contains 4 red balloons, 12 green balloons, 14 yellow balloons, and 7 orange balloons. What is the probability
Ostrovityanka [42]
There are 37 balloons total and there are 7 orange balloons. Therefore, the probability is 7/37.
5 0
3 years ago
A small manufacturing firm has 250 employees. Fifty have been employed for less than 5 years and 125 have been with the company
sukhopar [10]

Answer:

Step-by-step explanation:

Given that a small manufacturing firm has 250 employees. Fifty have been employed for less than 5 years and 125 have been with the company for over 10 years. So remaining 75 are between 5 and 10 years.

Suppose that one employee is selected at random from a list of the employees

A) Probability that the selected employee has been with the firm less than 5 years = \frac{50}{250 } \\= 0.20

B) Probability that the selected employee has been with the firm between 5 and 10 years

= \frac{75}{250 } \\= 0.30

C) Probability that the selected employee has been with the firm more than 10 years

= \frac{125}{250} =0.50

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P(C) = 0.5

P(A or B) = 0.2+0.3 = 0.5

P(A and C) = 0 (since A and C are disjoint)

7 0
3 years ago
10x + 7y=1<br> -5x-7y=24
nikitadnepr [17]
Okay, so since both y values share the same number, let's add both equations so the y values cancel out leaving us to solve for x.

10x+(-5x)=5x

7y+(-7y)=0

1+24=25

Now we have 5x=25

divide both sides by 5 and we have x=5

Now that we know x=5, we can plug it into one of the problems to find y.

Let's do 10(5) +7y=1   

50+7y=1  subtract 5 and we get 7y=-49

divide -7 from both sides and we get y=-7

so there you have it x=5 and y=-7
8 0
3 years ago
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