All categories

2 years ago

Find N(4) for the function, N(u) = 4.

Mathematics

1 answer:

lukranit [14]2 years ago

3 0

Answer:

N(4) = 4

Step-by-step explanation:

The given function is N(u) = 4, where N is the function and u is the independent variable.

Now, the value of the function N(u) is a constant and independent of u variable.

Therefore, for each and every value of the variable u the N(u) will be 4 and this is a constant function.

Hence, N(4) = 4 ( Answer )

You might be interested in

Write an expression showing 4 less than the number j.

Svetllana [295]

Answer:

j-4 is how you show 4 less than a number j

3 0

2 years ago

HELPPPP I WILL GIVE BRAINLYIST

Furkat [3]

Give me the characteristics and I’ll give you the examples

7 0

3 years ago

Read 2 more answers

Find the measure of the indicated angle. Round to the nearest degree.

slava [35]

Answer:

Step-by-step explanation:

Use SOH CAH TOA to recall how the trig functions fit on a triangle

SOH: Sin(Ф)= Opp / Hyp

CAH: Cos(Ф)= Adj / Hyp

TOA: Tan(Ф) = Opp / Adj

Adj = 14

Hyp = 26

∠X

so use

CAH

Cos(X) = 14/26

X = arcCos(14/26)

X = 57.421°

X = 57.4 ° ( rounded to nearest 10th )

∠X

Hyp = 46

Opp = 12

use SOH

Sin(x) = 12/46

X = arcSin(12/46)

X = 15.121°

X = 15.1 ° ( rounded to nearest 10th )

∠X

Adj = 29

Opp = 24

use TOA

Tan(x) = 29 / 24

X = arcTan( 29 /24)

X = 50.389

X = 50.4 ° ( rounded to nearest 10th )

∠X

Adj = 22

Opp = 6

use TOA agian

Tan(x) = 6 / 22

X = arcTan(6/22)

X = 5.194

X = 5.2 ° ( rounded to the nearest 10th )

8 0

3 years ago

There are 3 grams of sodium in 1⁄2 of a liter of soda. How much sodium is in 2⁄3 of a liter of soda?

denis-greek [22]

Answer:

4 grams in 2/3 liter of soda.

3 0

2 years ago

Simplify the expression 6C2

iVinArrow [24]

Answer:

$^6C_2=15$

Step-by-step explanation:

Recall the formula:

$^nC_r=\frac{n!}{(n-r)!r!}$

We apply this formula to simplify $^6C_2$

This implies that:

$^6C_2=\frac{6!}{(6-2)!2!}$

$^6C_2=\frac{6!}{4!2!}$

$^6C_2=\frac{6\times5\times4!}{4!\times 2\times1}$

This simplifies to

$^6C_2=\frac{6\times5}{2\times1}$

$^6C_2=\frac{3\times5}{1\times1}=15$

8 0

3 years ago