Which is bigger ⅞ or 5/8

2 answers:

8 0

Because 8 is equal 8 so you can see between 7 and 5 which one is bigger so 7 is bigger than 5 ⇒ 7/8 > 5/8 :)))
i hope this be helpful
* happy new year *

guapka [62]2 years ago

6 0

Seven of anything is almost always bigger than five of the same thing.

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(24 ÷ 6 - 2 + 5 × 3 × (-1 - 3) ÷ 4)^2 How do you solve this? Help me I need this ASAP!!

Bond [772]

Answer:

169

Step-by-step explanation:

PEMDAS

Parenthesis first

Add -1 and -3 which is -4

Divide 24 by 6 which is 4

(4-2+5*3*-4÷4)^2

(4-2-15)^2

(2-15)^2

(-13)^2

Which is 169

6 0

2 years ago

What is the answer to 6 2/7 * 2 1/ 10

mixas84 [53]

Answer:

13.2

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

From a piece of tin in the shape of a square 6 inches on a side, the largest possible circle is cut out. What is the ratio of th

wel

Answer:

$\sf \dfrac{1}{4} \pi \quad or \quad \dfrac{7}{9}$

Step-by-step explanation:

The width of a square is its side length.

The width of a circle is its diameter.

Therefore, the largest possible circle that can be cut out from a square is a circle whose diameter is equal in length to the side length of the square.

Formulas

$\sf \textsf{Area of a square}=s^2 \quad \textsf{(where s is the side length)}$

$\sf \textsf{Area of a circle}=\pi r^2 \quad \textsf{(where r is the radius)}$

$\sf \textsf{Radius of a circle}=\dfrac{1}{2}d \quad \textsf{(where d is the diameter)}$

If the diameter is equal to the side length of the square, then:
$\implies \sf r=\dfrac{1}{2}s$

Therefore:

$\begin{aligned}\implies \sf Area\:of\:circle & = \sf \pi \left(\dfrac{s}{2}\right)^2\\& = \sf \pi \left(\dfrac{s^2}{4}\right)\\& = \sf \dfrac{1}{4}\pi s^2 \end{aligned}$