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Gekata [30.6K]
3 years ago
6

Convert the equation to slope-intercept form: 4x + 3y = 15

Mathematics
1 answer:
Zielflug [23.3K]3 years ago
7 0

Answer:

y=-4x+5

Step-by-step explanation:

divide 15 by 3 to get rid of 3y

4x+y=5

subtract 4x

y=5-4x

thats the slope!

you could turn it around too and do y=-4x+5, but it doesnt matter

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Write a compound inequality for the graph shown below.
irina [24]

A compound inequality for the graph would be:

x >= 0 and x < 2

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4 years ago
Which property of operation could you use to show whether 7y + 7b + 3y and 7(y x b) + 3b are equivalent or not
Dmitry_Shevchenko [17]

Answer and explanation:

They are not equivalent because if we simplify the second expression, the result isn't the same:

7(y×b)+3b

= 7(yb)+3b

=7yb + 3b

Therefore 7yb+3b≠7y+7b+3y

And even though you meant

7(y+b)+3b

=7y+7b+3b

=7y+10b

7y+10b≠10y+7b

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3 years ago
Arnetta’s monthly gross pay is $4,200. Federal withholding is 16.05% of her pay. Her other deductions total $321.30. What is her
Westkost [7]

Answer:

c

Step-by-step explanation:

8 0
3 years ago
34,982 nearest 10,000
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4 0
4 years ago
Read 2 more answers
How to solve and respond.
son4ous [18]

Step-by-step explanation:

the error:

it is stated that

\frac{5x}{x+7} +\frac{7}{x} = \frac{5x}{x+7} +\frac{7(7)}{x+7}

subtract (5x)/(x+7) from both sides

\frac{7}{x}  = \frac{7(7)}{x+7}

multiply both sides by x + 7

7(x+7) = 49x

7x + 49 = 49x

subtract 7x from both sides to isolate x and its coefficient

49 = 42x

thus, this is only true when 49 = 42x. in order for these two equations to be equal, they must <em>always </em>be true, so this is wrong

the solution:

we want to express 7/x as (something) / (x+7). to do this, we can multiply 7/x  by 1.

anything divided by itself = 1. thus, if we multiply both the numerator and the denominator by something that turns x into (x+7), we can do what we want to do.

(x+7)/x * x turns x into (x+7), so we multiply both the numerator and denominator by (x+7)/x to get

\frac{7}{x} = \frac{7(x+7)/x}{x+7}

substitute this for 7/x in our original problem

\frac{5x}{x+7} +\frac{7(x+7)/x}{x+7} =  \frac{5x}{x+7} +\frac{(7x+49)/x}{x+7} = \frac{5x}{x+7} +\frac{7+49/x}{x+7} = \frac{5x+7+49/x}{x+7}

3 0
3 years ago
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