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tankabanditka [31]
3 years ago
15

What is 10 2/5 times 15 5/6! Thanks

Mathematics
1 answer:
svet-max [94.6K]3 years ago
3 0
10 2/5 times 15 5/7 is 5,720/35 which is 163 15/32 in mixed number
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What transformation preserves orientation but not size
Ket [755]

Answer:Reflection

Step-by-step explanation:

reflection does not preserve orientation

7 0
3 years ago
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Five years ago, Tim’s mom was three times Tim’s age today. Now their combined ages are 45. How old is Tim’s mom today?
klio [65]
His mother would be 30.

Hope this helps :)
4 0
3 years ago
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Joe is 5 years older than Sydney. The sum of their ages is 45. What is Sydney’s age?
sweet-ann [11.9K]

Answer:

20 years old

Step-by-step explanation:

Joe = J

Sydney = S

J = 5 + S

J + S = 45

Substitute

5 + S + S = 45

Add

5 + 2S = 45

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8 0
3 years ago
Find the size of each of the unknown angles.
kari74 [83]

Answer:

Angle a = 80°, Angle b = 55°, Angle c = 45°, Angle d = 80°

Step-by-step explanation:

To find the measure of Angle a, we add 55 and 45, then subtract the sum from 180.

180 - 100 = 80

Angle a is 80°.

Then, we solve for Angle b. Line segment CD is congruent to Line AB, so Angle b is congruent to 55°.

After that, we find Angle c. Line segment AC is congruent to Line segment BD, so Angle c is congruent to 45°.

Lastly, we solve for Angle d using the same method we used for Angle b and Angle c. Angle d is congruent to Angle a, so it measures 80°.

So, Angle a = 80°, Angle b = 55°, Angle c = 45°, Angle d = 80°.

8 0
3 years ago
What is the abscissa of the midpoint of the line segment whose endpoints are (5√2,2√3) and (√2,2√3)
xxMikexx [17]
Let
A------> <span>(5√2,2√3)
B------> </span><span>(√2,2√3)

we know that
</span>the abscissa<span> and the ordinate are respectively the first and second coordinate of a point in a coordinate system</span>
the abscissa is the coordinate x<span>

step 1
find the midpoint
ABx------> midpoint AB in the coordinate x
</span>ABy------> midpoint AB in the coordinate y
<span>
ABx=[5</span>√2+√2]/2------> 6√2/2-----> 3√2
ABy=[2√3+2√3]/2------> 4√3/2-----> 2√3

the midpoint AB is (3√2,2√3)

the answer is
the abscissa of the midpoint of the line segment  is 3√2

see the attached figure

3 0
3 years ago
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