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larisa86 [58]
3 years ago
11

2. angle ABE = angle MNP Write another valid congruency statement:​

Mathematics
1 answer:
Free_Kalibri [48]3 years ago
4 0

Given:

\Delta ABE\cong \Delta MNP

To find:

The congruent angles and sides, then find the another valid congruency statement.

Solution:

We have,

\Delta ABE\cong \Delta MNP

We know that, corresponding parts of congruent triangles are congruent (CPCTC).

Using CPCTC, we get

Angles:

\angle A\cong \angle M

\angle B\cong \angle N

\angle E\cong \angle P

Sides:

AB\cong MN

BE\cong NP

AE\cong MP

The another congruent statement is \Delta BEA\cong \Delta NPM.

Therefore, the required table is

Angles                                              Sides

\angle A\cong \angle M                                        AB\cong MN

\angle B\cong \angle N                                        BE\cong NP

\angle E\cong \angle P                                        AE\cong MP

The another congruent statement is \Delta BEA\cong \Delta NPM.

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Since the ordered pairs are: (-2, 5), (-1, 1), (2, -2), and (5, 2), we see that the output of this function is: 5, 1, -2, 2.

Thus, choice D is correct.

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Answer:

The value of r=\frac{-106}{47}

The value of x=\frac{83}{32}

Step-by-step explanation:

Given that,

A) \frac{2r-2}{7r+10} = \frac{9}{8}

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Identify the values that should be written to complete the X diagram.
cestrela7 [59]

Answer:

See the attachment for what goes on your X diagram.

Rewrite: x² -7x +4x -28

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Step-by-step explanation:

The given quadratic is ...

... x² -3x -28 . . . . . a=1, b=-3, c=-28

a) The value at the top of the X diagram is the product a·c = 1·(-28) = -28.

The value at the bottom of the X diagram is the coefficient b = -3.

The values on the sides of the diagram are the factors of -28 that add up to make -3. These are -7 and 4. That is, ...

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b) Since the two values on the sides of the diagram add up to give "b", the value of "b" in the equation can be rewritten as the sum of these two numbers. Doing that, we have ...

... x² -3x -28

... = x² +(-7+4)x -28

... = x² -7x +4x -28 . . . . . . order does not matter. It could also be x² +4x -7x -28

c) We can group pairs of terms in the rewritten expression and factor each pair.

... = (x² -7x) +(4x -28) . . . . . first pair has a common factor of x; second pair, 4

... = x(x -7) +4(x -7) . . . . . . . these terms now have a common factor: (x -7)

... = (x +4)(x -7) . . . . . . . . . . the complete factorization of x² -3x -28

3 0
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